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Flattening the sub-lists

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  3 hours ago
  

  
  
  
  

add a comment | 

2

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

$endgroup$

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  $begingroup$
  try Flatten[list,1]
  $endgroup$
  – J42161217
  6 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  One can also consider using Join @@ yourlist.
  $endgroup$
  – Αλέξανδρος Ζεγγ
  3 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

Is there a way to flatten the sub-lists within a list?

Transform

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Into

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I know I can do

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

I am wondering whether there are some dedicated functions for such sub-list flattening?

list-manipulation

share|improve this question

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

$endgroup$

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

Flatten /@ 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this question

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

share|improve this question

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

edited 6 hours ago

m0nhawk

2,92711532

edited 6 hours ago

m0nhawk

2,92711532

asked 6 hours ago

bakerbaker

463

asked 6 hours ago

bakerbaker

463

2 Answers
2

active

oldest

votes

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

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7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

7

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

add a comment | 

$begingroup$

You are doing redundant step with /@, Flatten can make this directly:

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

$endgroup$

Flatten[1, x, 2, x, 3, x, 4, x, 5, 
 x, 6, x, 7, x, 8, x, 9, x, 10, x, 1]
(* 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, 
 x, 9, x, 10, x *)

share|improve this answer

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

answered 6 hours ago

m0nhawkm0nhawk

2,92711532

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

0

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

add a comment | 

$begingroup$

Yes, there is a built-in function for what you want to do.

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x

share|improve this answer

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

$endgroup$

data = 1, x, 2, x, 3, x, 4, x, 5, x, 6, x, 7, x, 8, x, 9, x, 10, x;
Catenate @ data

share|improve this answer

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200

answered 10 mins ago

m_goldbergm_goldberg

89.1k873200