Why is high voltage dangerous? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Moderator Election Q&A - Question CollectionWhich dissipates more power, a small or big resistor?Is the same amount of electricity used for ceiling and table fans on different speeds?Why does electricity need wires to flow?Why are high voltage lines “high voltage?”Heat loss using alternating currentIf the Earth is a good conductor of electricity, why don't people get electrocuted every time they touch the Earth?Transformer vs Inductor for lighting a bulb or any other applianceCan a gym be built to supply electricity to homes?What is the purpose of having two coils in a tranformer?How to combine multiple transformers in series?Circuit problem with different resistors and analysis of voltage of electrons

Did Xerox really develop the first LAN?

How can whole tone melodies sound more interesting?

Withdrew £2800, but only £2000 shows as withdrawn on online banking; what are my obligations?

Java 8 stream max() function argument type Comparator vs Comparable

Can a non-EU citizen traveling with me come with me through the EU passport line?

Can Pao de Queijo, and similar foods, be kosher for Passover?

3 doors, three guards, one stone

How to bypass password on Windows XP account?

What is a Meta algorithm?

When -s is used with third person singular. What's its use in this context?

How does cp -a work

What would be the ideal power source for a cybernetic eye?

How do I stop a creek from eroding my steep embankment?

Stars Make Stars

ListPlot join points by nearest neighbor rather than order

Is the Standard Deduction better than Itemized when both are the same amount?

Should I use Javascript Classes or Apex Classes in Lightning Web Components?

How widely used is the term Treppenwitz? Is it something that most Germans know?

Bonus calculation: Am I making a mountain out of a molehill?

How to deal with a team lead who never gives me credit?

Is above average number of years spent on PhD considered a red flag in future academia or industry positions?

What are the motives behind Cersei's orders given to Bronn?

Is there a Spanish version of "dot your i's and cross your t's" that includes the letter 'ñ'?

Is it true that "carbohydrates are of no use for the basal metabolic need"?



Why is high voltage dangerous?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Moderator Election Q&A - Question CollectionWhich dissipates more power, a small or big resistor?Is the same amount of electricity used for ceiling and table fans on different speeds?Why does electricity need wires to flow?Why are high voltage lines “high voltage?”Heat loss using alternating currentIf the Earth is a good conductor of electricity, why don't people get electrocuted every time they touch the Earth?Transformer vs Inductor for lighting a bulb or any other applianceCan a gym be built to supply electricity to homes?What is the purpose of having two coils in a tranformer?How to combine multiple transformers in series?Circuit problem with different resistors and analysis of voltage of electrons










2












$begingroup$


High $V$ low $A$ electricity is transformed into low $V$ high $A$ through a step down transformer for safer use in homes.



But how is it any safer? The wattage is the same for the pre-transformer charge flow, and the post-transformer charge flow. The energy both charge flows transfer is also the same.



Edit: by safety I’m referring to human contact










share|cite|improve this question









New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 2




    $begingroup$
    At high voltage, you are more likely to have dielectric breakdown.
    $endgroup$
    – IamAStudent
    5 hours ago










  • $begingroup$
    What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    You may find this question relevant: physics.stackexchange.com/q/141331.
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
    $endgroup$
    – Ubaid Hassan
    5 hours ago










  • $begingroup$
    that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
    $endgroup$
    – Ubaid Hassan
    5 hours ago















2












$begingroup$


High $V$ low $A$ electricity is transformed into low $V$ high $A$ through a step down transformer for safer use in homes.



But how is it any safer? The wattage is the same for the pre-transformer charge flow, and the post-transformer charge flow. The energy both charge flows transfer is also the same.



Edit: by safety I’m referring to human contact










share|cite|improve this question









New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 2




    $begingroup$
    At high voltage, you are more likely to have dielectric breakdown.
    $endgroup$
    – IamAStudent
    5 hours ago










  • $begingroup$
    What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    You may find this question relevant: physics.stackexchange.com/q/141331.
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
    $endgroup$
    – Ubaid Hassan
    5 hours ago










  • $begingroup$
    that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
    $endgroup$
    – Ubaid Hassan
    5 hours ago













2












2








2





$begingroup$


High $V$ low $A$ electricity is transformed into low $V$ high $A$ through a step down transformer for safer use in homes.



But how is it any safer? The wattage is the same for the pre-transformer charge flow, and the post-transformer charge flow. The energy both charge flows transfer is also the same.



Edit: by safety I’m referring to human contact










share|cite|improve this question









New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




High $V$ low $A$ electricity is transformed into low $V$ high $A$ through a step down transformer for safer use in homes.



But how is it any safer? The wattage is the same for the pre-transformer charge flow, and the post-transformer charge flow. The energy both charge flows transfer is also the same.



Edit: by safety I’m referring to human contact







electricity electric-current voltage biology






share|cite|improve this question









New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 36 mins ago







Ubaid Hassan













New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









Ubaid HassanUbaid Hassan

37513




37513




New contributor




Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Ubaid Hassan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 2




    $begingroup$
    At high voltage, you are more likely to have dielectric breakdown.
    $endgroup$
    – IamAStudent
    5 hours ago










  • $begingroup$
    What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    You may find this question relevant: physics.stackexchange.com/q/141331.
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
    $endgroup$
    – Ubaid Hassan
    5 hours ago










  • $begingroup$
    that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
    $endgroup$
    – Ubaid Hassan
    5 hours ago












  • 2




    $begingroup$
    At high voltage, you are more likely to have dielectric breakdown.
    $endgroup$
    – IamAStudent
    5 hours ago










  • $begingroup$
    What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    You may find this question relevant: physics.stackexchange.com/q/141331.
    $endgroup$
    – DanielSank
    5 hours ago











  • $begingroup$
    The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
    $endgroup$
    – Ubaid Hassan
    5 hours ago










  • $begingroup$
    that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
    $endgroup$
    – Ubaid Hassan
    5 hours ago







2




2




$begingroup$
At high voltage, you are more likely to have dielectric breakdown.
$endgroup$
– IamAStudent
5 hours ago




$begingroup$
At high voltage, you are more likely to have dielectric breakdown.
$endgroup$
– IamAStudent
5 hours ago












$begingroup$
What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
$endgroup$
– DanielSank
5 hours ago





$begingroup$
What happens if I take a gigantic battery, i.e. one that can supply up to one kiloamp of current, with a 1 V voltage and connect its terminals to your hands? Now what happens if I connect a smaller, battery i.e. one that can supply only up to 1 amp, with a voltage of 1 kV, across your hands?
$endgroup$
– DanielSank
5 hours ago













$begingroup$
You may find this question relevant: physics.stackexchange.com/q/141331.
$endgroup$
– DanielSank
5 hours ago





$begingroup$
You may find this question relevant: physics.stackexchange.com/q/141331.
$endgroup$
– DanielSank
5 hours ago













$begingroup$
The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
$endgroup$
– Ubaid Hassan
5 hours ago




$begingroup$
The gigantic battery would transfer 100w to me through my hands while the smaller battery transfers 1000w thereby being more dangerous?
$endgroup$
– Ubaid Hassan
5 hours ago












$begingroup$
that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
$endgroup$
– Ubaid Hassan
5 hours ago




$begingroup$
that post you linked me created more questions for me than it answered. ;-; What is that OP talking about? A low resistance=stronger heating effect? I thought it would be the opposite.
$endgroup$
– Ubaid Hassan
5 hours ago










6 Answers
6






active

oldest

votes


















2












$begingroup$

As @David White has pointed out, at low voltages the body's skin impedance when dry is very high. Therefore no matter how much current is available from the voltage source, only a small amount of current will flow through the body due to its high skin impedance per Ohm's law. So a 12 volt lead acid battery which has plenty of amps available will not cause an electric shock. (It could certainly cause burns if it contacts metal in contact with the skin).



The National Electrical Code (NEC) generally considers 60 Hz ac rms voltages that are less than 30 vrms at the output of an isolating transformer to be low risk with respect to electric shock under dry contact conditions. For this reason circuits connected to the secondary of a step down isolating transformer with output voltage less than 30 vrms is generally considered low risk of electric shock. These transformers, if they also comply with output current/power limits for fire considerations, are sometimes referred to as NEC Class 2 transformers.



When the voltage gets higher, or the skin gets wet, the skin impedance falls. Now the limiting factor is how much current is available from the voltage source. That will depend on the source impedance. For ac 60 Hz rms current the threshold of startle reaction is generally considered to be in the range of 0.5-5.0 mA. GFCI's are designed to trip at nominal 5 mA. From 5-10 mA the inability to let go becomes a possibility, depending on whether a child or adult. As the current through the body goes beyond 10-20 mA the the risk of ventricular fibrillation, and at very high currents, cardiac arrest, becomes greater.



There are many other factors involved in the risk of electric shock, too many to go into here. For example, at higher frequencies the skin impedance also drops (due to its capacitance). On the other hand, at higher frequencies a higher current is needed to produce the same physiological effect.



Various safety standards, in the US and International, publish voltage and current limits to reduce the risk of electric shock. They should be consulted.



ADDENDUM:



With regard to your following statement:



high V low A electricity is transformed into low V high A through a step down transformer for safer use in homes



If you are talking about the high voltage outside the home being stepped down to 120/240 vac by the utility transformer on the pole or under ground, the output voltages from those transformers do pose a risk of electric shock.



If, on the other hand, you are talking about step down transformers that step 120 vac down to 30 vac or less, such as transformers used in electronic equipment, or bell ringing transformers used within walls to power door bells, as I described above, then these transformers do reduce the risk of electric shock because the body impedance is very high at low voltage.



With regard to you comment to @David White, it doesn’t matter how much current is available from the step down transformer if the body impedance won’t allow it to flow. It is the current that actually flows in the body that determines the risk of electric shock.



Hope this helps.






share|cite|improve this answer











$endgroup$




















    0












    $begingroup$

    Ohm's law is given by the equation $V=IR$. This equation can be solved for the current that exists in a conductor that has a given voltage difference across it, as $I=V/R$.



    A human being with dry skin has a very high electrical resistivity, on the order of 100,000 ohms to a few million ohms. This is a good thing, because such a high resistance ensures a very small current flow when a human being becomes grounded against household voltage. However, there are various estimates of the minimum fatal dose of current through a human heart, but a common estimate is that 10 milliamps through a human heart will interfere with the electrical conductivity of the heart enough to produce a fatal arrhythmia. Thus, household current through a person will be small, but the minimal lethal current through that person is also small, so it is safest to run a household on a very low voltage to minimize the risk of a fatal electrical current going through any people in that house.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
      $endgroup$
      – Ubaid Hassan
      4 hours ago










    • $begingroup$
      No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
      $endgroup$
      – David White
      2 hours ago


















    0












    $begingroup$

    You are confused with the same wattage, supposing that wattage is determined by pre-transformed $V_1$ and $A_1$.



    But the order of things is other:




    • $V_1$ is changed to $V_2$,

    • then some resistor (a human body) is connected to the secondary, low voltage ($V_2)$ circuit,

    • and the impedance of that resistor determines (by Ohm law) the $A_2$ (and - consequently - the wattage $V_2cdot A_2$, too).

    Only after determining $A_2$ is determined $A_1$, too, to fullfil the equation $A_2/A_1 = V_1/V_2.$

    Symbolically:



    $$V_1 implies V_2\
    V_2/ R implies A_2\
    A_2 implies A_1$$






    share|cite|improve this answer











    $endgroup$












    • $begingroup$
      why not the reverse? why not have the current going into the resistor and then determining the voltage?
      $endgroup$
      – Ubaid Hassan
      3 hours ago










    • $begingroup$
      Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
      $endgroup$
      – MarianD
      2 hours ago











    • $begingroup$
      @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
      $endgroup$
      – Jahan Claes
      2 hours ago










    • $begingroup$
      @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
      $endgroup$
      – Jahan Claes
      2 hours ago










    • $begingroup$
      I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
      $endgroup$
      – Ubaid Hassan
      34 mins ago


















    0












    $begingroup$

    Most power sources have a fixed voltage (batteries, phone chargers, wall sockets) and can provide up to a certain limit amperes of current.



    Phone chargers: always provide 5V, some are able to provide up to 2A while others can provide only 1A. The phone is responsible to "negotiate" with the charger how much current it draws so it doesn't damage the charger.



    Wall sockets: always provide 230V AC (in Germany), but how much current is drawn depends on the connected device. Very little will be drawn by a phone charger, far more by a vacuum cleaner or an electric heater. Circuit breakers are in place that limit the current to 16A (usually) to prevent overheating wires.



    So remember:



    • Voltage is a property of a electrical source.

    • Current will depend on the connected device(s)

    Usually, if a device is connected to a variable voltage source, a higher voltage leads to a higher current. That is why high voltages are dangerous.






    share|cite|improve this answer









    $endgroup$




















      0












      $begingroup$

      When you get a shock, the current is tiny. Only a few mA. You don't put much of a load on your household system. It is not like the lights in the house dim or anything. So the current capacity of the wires in the house is not really the issue.



      But the higher the voltage, the more current flows through your body. If you get a 10mA shock from 120V, then you would get a 20mA shock from 240V. The sensation of being shocked, and the risk of permanent harm, are both related to the amount of current flowing. Greater current is more unpleasant, and ultimately greater risk of harm or death.






      share|cite|improve this answer








      New contributor




      mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$




















        0












        $begingroup$

        When electrical engineers work on circuits that transfer energy, the characteristic they use is called "impedance". To get power moved most efficiently, they "match" the impedances. There's a wikipedia article: https://en.wikipedia.org/wiki/Impedance_matching



        Now impedance is simply the R in V=IR so we can compute the impedances for high and low voltage power and compare them with the impedance of a human.



        Keeping the power at 2.4KW, let's compare 120 and 240V:



        120V 20A => 6 ohms
        240V 10A => 24 ohms



        Note that the impedance was much higher with the higher voltage.



        And what is the impedance of a human? The first hit on DuckDuckGo for me is a Fluke article:



        "Human impedance variability has been shown to vary from 25 ohms to 180 ohms"
        https://support.fluke.com/biomedical/download/asset/ppp085_impedance_educational.pdf



        So we see that when shocking humans, our impedances will match better (and the shock will include more power) if we have the higher voltage.






        share|cite|improve this answer









        $endgroup$













          Your Answer








          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "151"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );






          Ubaid Hassan is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f472964%2fwhy-is-high-voltage-dangerous%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          6 Answers
          6






          active

          oldest

          votes








          6 Answers
          6






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          As @David White has pointed out, at low voltages the body's skin impedance when dry is very high. Therefore no matter how much current is available from the voltage source, only a small amount of current will flow through the body due to its high skin impedance per Ohm's law. So a 12 volt lead acid battery which has plenty of amps available will not cause an electric shock. (It could certainly cause burns if it contacts metal in contact with the skin).



          The National Electrical Code (NEC) generally considers 60 Hz ac rms voltages that are less than 30 vrms at the output of an isolating transformer to be low risk with respect to electric shock under dry contact conditions. For this reason circuits connected to the secondary of a step down isolating transformer with output voltage less than 30 vrms is generally considered low risk of electric shock. These transformers, if they also comply with output current/power limits for fire considerations, are sometimes referred to as NEC Class 2 transformers.



          When the voltage gets higher, or the skin gets wet, the skin impedance falls. Now the limiting factor is how much current is available from the voltage source. That will depend on the source impedance. For ac 60 Hz rms current the threshold of startle reaction is generally considered to be in the range of 0.5-5.0 mA. GFCI's are designed to trip at nominal 5 mA. From 5-10 mA the inability to let go becomes a possibility, depending on whether a child or adult. As the current through the body goes beyond 10-20 mA the the risk of ventricular fibrillation, and at very high currents, cardiac arrest, becomes greater.



          There are many other factors involved in the risk of electric shock, too many to go into here. For example, at higher frequencies the skin impedance also drops (due to its capacitance). On the other hand, at higher frequencies a higher current is needed to produce the same physiological effect.



          Various safety standards, in the US and International, publish voltage and current limits to reduce the risk of electric shock. They should be consulted.



          ADDENDUM:



          With regard to your following statement:



          high V low A electricity is transformed into low V high A through a step down transformer for safer use in homes



          If you are talking about the high voltage outside the home being stepped down to 120/240 vac by the utility transformer on the pole or under ground, the output voltages from those transformers do pose a risk of electric shock.



          If, on the other hand, you are talking about step down transformers that step 120 vac down to 30 vac or less, such as transformers used in electronic equipment, or bell ringing transformers used within walls to power door bells, as I described above, then these transformers do reduce the risk of electric shock because the body impedance is very high at low voltage.



          With regard to you comment to @David White, it doesn’t matter how much current is available from the step down transformer if the body impedance won’t allow it to flow. It is the current that actually flows in the body that determines the risk of electric shock.



          Hope this helps.






          share|cite|improve this answer











          $endgroup$

















            2












            $begingroup$

            As @David White has pointed out, at low voltages the body's skin impedance when dry is very high. Therefore no matter how much current is available from the voltage source, only a small amount of current will flow through the body due to its high skin impedance per Ohm's law. So a 12 volt lead acid battery which has plenty of amps available will not cause an electric shock. (It could certainly cause burns if it contacts metal in contact with the skin).



            The National Electrical Code (NEC) generally considers 60 Hz ac rms voltages that are less than 30 vrms at the output of an isolating transformer to be low risk with respect to electric shock under dry contact conditions. For this reason circuits connected to the secondary of a step down isolating transformer with output voltage less than 30 vrms is generally considered low risk of electric shock. These transformers, if they also comply with output current/power limits for fire considerations, are sometimes referred to as NEC Class 2 transformers.



            When the voltage gets higher, or the skin gets wet, the skin impedance falls. Now the limiting factor is how much current is available from the voltage source. That will depend on the source impedance. For ac 60 Hz rms current the threshold of startle reaction is generally considered to be in the range of 0.5-5.0 mA. GFCI's are designed to trip at nominal 5 mA. From 5-10 mA the inability to let go becomes a possibility, depending on whether a child or adult. As the current through the body goes beyond 10-20 mA the the risk of ventricular fibrillation, and at very high currents, cardiac arrest, becomes greater.



            There are many other factors involved in the risk of electric shock, too many to go into here. For example, at higher frequencies the skin impedance also drops (due to its capacitance). On the other hand, at higher frequencies a higher current is needed to produce the same physiological effect.



            Various safety standards, in the US and International, publish voltage and current limits to reduce the risk of electric shock. They should be consulted.



            ADDENDUM:



            With regard to your following statement:



            high V low A electricity is transformed into low V high A through a step down transformer for safer use in homes



            If you are talking about the high voltage outside the home being stepped down to 120/240 vac by the utility transformer on the pole or under ground, the output voltages from those transformers do pose a risk of electric shock.



            If, on the other hand, you are talking about step down transformers that step 120 vac down to 30 vac or less, such as transformers used in electronic equipment, or bell ringing transformers used within walls to power door bells, as I described above, then these transformers do reduce the risk of electric shock because the body impedance is very high at low voltage.



            With regard to you comment to @David White, it doesn’t matter how much current is available from the step down transformer if the body impedance won’t allow it to flow. It is the current that actually flows in the body that determines the risk of electric shock.



            Hope this helps.






            share|cite|improve this answer











            $endgroup$















              2












              2








              2





              $begingroup$

              As @David White has pointed out, at low voltages the body's skin impedance when dry is very high. Therefore no matter how much current is available from the voltage source, only a small amount of current will flow through the body due to its high skin impedance per Ohm's law. So a 12 volt lead acid battery which has plenty of amps available will not cause an electric shock. (It could certainly cause burns if it contacts metal in contact with the skin).



              The National Electrical Code (NEC) generally considers 60 Hz ac rms voltages that are less than 30 vrms at the output of an isolating transformer to be low risk with respect to electric shock under dry contact conditions. For this reason circuits connected to the secondary of a step down isolating transformer with output voltage less than 30 vrms is generally considered low risk of electric shock. These transformers, if they also comply with output current/power limits for fire considerations, are sometimes referred to as NEC Class 2 transformers.



              When the voltage gets higher, or the skin gets wet, the skin impedance falls. Now the limiting factor is how much current is available from the voltage source. That will depend on the source impedance. For ac 60 Hz rms current the threshold of startle reaction is generally considered to be in the range of 0.5-5.0 mA. GFCI's are designed to trip at nominal 5 mA. From 5-10 mA the inability to let go becomes a possibility, depending on whether a child or adult. As the current through the body goes beyond 10-20 mA the the risk of ventricular fibrillation, and at very high currents, cardiac arrest, becomes greater.



              There are many other factors involved in the risk of electric shock, too many to go into here. For example, at higher frequencies the skin impedance also drops (due to its capacitance). On the other hand, at higher frequencies a higher current is needed to produce the same physiological effect.



              Various safety standards, in the US and International, publish voltage and current limits to reduce the risk of electric shock. They should be consulted.



              ADDENDUM:



              With regard to your following statement:



              high V low A electricity is transformed into low V high A through a step down transformer for safer use in homes



              If you are talking about the high voltage outside the home being stepped down to 120/240 vac by the utility transformer on the pole or under ground, the output voltages from those transformers do pose a risk of electric shock.



              If, on the other hand, you are talking about step down transformers that step 120 vac down to 30 vac or less, such as transformers used in electronic equipment, or bell ringing transformers used within walls to power door bells, as I described above, then these transformers do reduce the risk of electric shock because the body impedance is very high at low voltage.



              With regard to you comment to @David White, it doesn’t matter how much current is available from the step down transformer if the body impedance won’t allow it to flow. It is the current that actually flows in the body that determines the risk of electric shock.



              Hope this helps.






              share|cite|improve this answer











              $endgroup$



              As @David White has pointed out, at low voltages the body's skin impedance when dry is very high. Therefore no matter how much current is available from the voltage source, only a small amount of current will flow through the body due to its high skin impedance per Ohm's law. So a 12 volt lead acid battery which has plenty of amps available will not cause an electric shock. (It could certainly cause burns if it contacts metal in contact with the skin).



              The National Electrical Code (NEC) generally considers 60 Hz ac rms voltages that are less than 30 vrms at the output of an isolating transformer to be low risk with respect to electric shock under dry contact conditions. For this reason circuits connected to the secondary of a step down isolating transformer with output voltage less than 30 vrms is generally considered low risk of electric shock. These transformers, if they also comply with output current/power limits for fire considerations, are sometimes referred to as NEC Class 2 transformers.



              When the voltage gets higher, or the skin gets wet, the skin impedance falls. Now the limiting factor is how much current is available from the voltage source. That will depend on the source impedance. For ac 60 Hz rms current the threshold of startle reaction is generally considered to be in the range of 0.5-5.0 mA. GFCI's are designed to trip at nominal 5 mA. From 5-10 mA the inability to let go becomes a possibility, depending on whether a child or adult. As the current through the body goes beyond 10-20 mA the the risk of ventricular fibrillation, and at very high currents, cardiac arrest, becomes greater.



              There are many other factors involved in the risk of electric shock, too many to go into here. For example, at higher frequencies the skin impedance also drops (due to its capacitance). On the other hand, at higher frequencies a higher current is needed to produce the same physiological effect.



              Various safety standards, in the US and International, publish voltage and current limits to reduce the risk of electric shock. They should be consulted.



              ADDENDUM:



              With regard to your following statement:



              high V low A electricity is transformed into low V high A through a step down transformer for safer use in homes



              If you are talking about the high voltage outside the home being stepped down to 120/240 vac by the utility transformer on the pole or under ground, the output voltages from those transformers do pose a risk of electric shock.



              If, on the other hand, you are talking about step down transformers that step 120 vac down to 30 vac or less, such as transformers used in electronic equipment, or bell ringing transformers used within walls to power door bells, as I described above, then these transformers do reduce the risk of electric shock because the body impedance is very high at low voltage.



              With regard to you comment to @David White, it doesn’t matter how much current is available from the step down transformer if the body impedance won’t allow it to flow. It is the current that actually flows in the body that determines the risk of electric shock.



              Hope this helps.







              share|cite|improve this answer














              share|cite|improve this answer



              share|cite|improve this answer








              edited 4 hours ago

























              answered 4 hours ago









              Bob DBob D

              4,7052318




              4,7052318





















                  0












                  $begingroup$

                  Ohm's law is given by the equation $V=IR$. This equation can be solved for the current that exists in a conductor that has a given voltage difference across it, as $I=V/R$.



                  A human being with dry skin has a very high electrical resistivity, on the order of 100,000 ohms to a few million ohms. This is a good thing, because such a high resistance ensures a very small current flow when a human being becomes grounded against household voltage. However, there are various estimates of the minimum fatal dose of current through a human heart, but a common estimate is that 10 milliamps through a human heart will interfere with the electrical conductivity of the heart enough to produce a fatal arrhythmia. Thus, household current through a person will be small, but the minimal lethal current through that person is also small, so it is safest to run a household on a very low voltage to minimize the risk of a fatal electrical current going through any people in that house.






                  share|cite|improve this answer









                  $endgroup$












                  • $begingroup$
                    I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                    $endgroup$
                    – Ubaid Hassan
                    4 hours ago










                  • $begingroup$
                    No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                    $endgroup$
                    – David White
                    2 hours ago















                  0












                  $begingroup$

                  Ohm's law is given by the equation $V=IR$. This equation can be solved for the current that exists in a conductor that has a given voltage difference across it, as $I=V/R$.



                  A human being with dry skin has a very high electrical resistivity, on the order of 100,000 ohms to a few million ohms. This is a good thing, because such a high resistance ensures a very small current flow when a human being becomes grounded against household voltage. However, there are various estimates of the minimum fatal dose of current through a human heart, but a common estimate is that 10 milliamps through a human heart will interfere with the electrical conductivity of the heart enough to produce a fatal arrhythmia. Thus, household current through a person will be small, but the minimal lethal current through that person is also small, so it is safest to run a household on a very low voltage to minimize the risk of a fatal electrical current going through any people in that house.






                  share|cite|improve this answer









                  $endgroup$












                  • $begingroup$
                    I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                    $endgroup$
                    – Ubaid Hassan
                    4 hours ago










                  • $begingroup$
                    No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                    $endgroup$
                    – David White
                    2 hours ago













                  0












                  0








                  0





                  $begingroup$

                  Ohm's law is given by the equation $V=IR$. This equation can be solved for the current that exists in a conductor that has a given voltage difference across it, as $I=V/R$.



                  A human being with dry skin has a very high electrical resistivity, on the order of 100,000 ohms to a few million ohms. This is a good thing, because such a high resistance ensures a very small current flow when a human being becomes grounded against household voltage. However, there are various estimates of the minimum fatal dose of current through a human heart, but a common estimate is that 10 milliamps through a human heart will interfere with the electrical conductivity of the heart enough to produce a fatal arrhythmia. Thus, household current through a person will be small, but the minimal lethal current through that person is also small, so it is safest to run a household on a very low voltage to minimize the risk of a fatal electrical current going through any people in that house.






                  share|cite|improve this answer









                  $endgroup$



                  Ohm's law is given by the equation $V=IR$. This equation can be solved for the current that exists in a conductor that has a given voltage difference across it, as $I=V/R$.



                  A human being with dry skin has a very high electrical resistivity, on the order of 100,000 ohms to a few million ohms. This is a good thing, because such a high resistance ensures a very small current flow when a human being becomes grounded against household voltage. However, there are various estimates of the minimum fatal dose of current through a human heart, but a common estimate is that 10 milliamps through a human heart will interfere with the electrical conductivity of the heart enough to produce a fatal arrhythmia. Thus, household current through a person will be small, but the minimal lethal current through that person is also small, so it is safest to run a household on a very low voltage to minimize the risk of a fatal electrical current going through any people in that house.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 5 hours ago









                  David WhiteDavid White

                  4,8812620




                  4,8812620











                  • $begingroup$
                    I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                    $endgroup$
                    – Ubaid Hassan
                    4 hours ago










                  • $begingroup$
                    No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                    $endgroup$
                    – David White
                    2 hours ago
















                  • $begingroup$
                    I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                    $endgroup$
                    – Ubaid Hassan
                    4 hours ago










                  • $begingroup$
                    No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                    $endgroup$
                    – David White
                    2 hours ago















                  $begingroup$
                  I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                  $endgroup$
                  – Ubaid Hassan
                  4 hours ago




                  $begingroup$
                  I understand that a low voltage on a human means a lower current because 10000I=V, but that low voltage in this case comes with the trade off of a high current due to the step down transformer used for the house. this means that a low voltage would deliver large current to the human would it not?
                  $endgroup$
                  – Ubaid Hassan
                  4 hours ago












                  $begingroup$
                  No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                  $endgroup$
                  – David White
                  2 hours ago




                  $begingroup$
                  No. A human being is also a conductor, and as such, a human being also follows Ohm's law.
                  $endgroup$
                  – David White
                  2 hours ago











                  0












                  $begingroup$

                  You are confused with the same wattage, supposing that wattage is determined by pre-transformed $V_1$ and $A_1$.



                  But the order of things is other:




                  • $V_1$ is changed to $V_2$,

                  • then some resistor (a human body) is connected to the secondary, low voltage ($V_2)$ circuit,

                  • and the impedance of that resistor determines (by Ohm law) the $A_2$ (and - consequently - the wattage $V_2cdot A_2$, too).

                  Only after determining $A_2$ is determined $A_1$, too, to fullfil the equation $A_2/A_1 = V_1/V_2.$

                  Symbolically:



                  $$V_1 implies V_2\
                  V_2/ R implies A_2\
                  A_2 implies A_1$$






                  share|cite|improve this answer











                  $endgroup$












                  • $begingroup$
                    why not the reverse? why not have the current going into the resistor and then determining the voltage?
                    $endgroup$
                    – Ubaid Hassan
                    3 hours ago










                  • $begingroup$
                    Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                    $endgroup$
                    – MarianD
                    2 hours ago











                  • $begingroup$
                    @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                    $endgroup$
                    – Ubaid Hassan
                    34 mins ago















                  0












                  $begingroup$

                  You are confused with the same wattage, supposing that wattage is determined by pre-transformed $V_1$ and $A_1$.



                  But the order of things is other:




                  • $V_1$ is changed to $V_2$,

                  • then some resistor (a human body) is connected to the secondary, low voltage ($V_2)$ circuit,

                  • and the impedance of that resistor determines (by Ohm law) the $A_2$ (and - consequently - the wattage $V_2cdot A_2$, too).

                  Only after determining $A_2$ is determined $A_1$, too, to fullfil the equation $A_2/A_1 = V_1/V_2.$

                  Symbolically:



                  $$V_1 implies V_2\
                  V_2/ R implies A_2\
                  A_2 implies A_1$$






                  share|cite|improve this answer











                  $endgroup$












                  • $begingroup$
                    why not the reverse? why not have the current going into the resistor and then determining the voltage?
                    $endgroup$
                    – Ubaid Hassan
                    3 hours ago










                  • $begingroup$
                    Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                    $endgroup$
                    – MarianD
                    2 hours ago











                  • $begingroup$
                    @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                    $endgroup$
                    – Ubaid Hassan
                    34 mins ago













                  0












                  0








                  0





                  $begingroup$

                  You are confused with the same wattage, supposing that wattage is determined by pre-transformed $V_1$ and $A_1$.



                  But the order of things is other:




                  • $V_1$ is changed to $V_2$,

                  • then some resistor (a human body) is connected to the secondary, low voltage ($V_2)$ circuit,

                  • and the impedance of that resistor determines (by Ohm law) the $A_2$ (and - consequently - the wattage $V_2cdot A_2$, too).

                  Only after determining $A_2$ is determined $A_1$, too, to fullfil the equation $A_2/A_1 = V_1/V_2.$

                  Symbolically:



                  $$V_1 implies V_2\
                  V_2/ R implies A_2\
                  A_2 implies A_1$$






                  share|cite|improve this answer











                  $endgroup$



                  You are confused with the same wattage, supposing that wattage is determined by pre-transformed $V_1$ and $A_1$.



                  But the order of things is other:




                  • $V_1$ is changed to $V_2$,

                  • then some resistor (a human body) is connected to the secondary, low voltage ($V_2)$ circuit,

                  • and the impedance of that resistor determines (by Ohm law) the $A_2$ (and - consequently - the wattage $V_2cdot A_2$, too).

                  Only after determining $A_2$ is determined $A_1$, too, to fullfil the equation $A_2/A_1 = V_1/V_2.$

                  Symbolically:



                  $$V_1 implies V_2\
                  V_2/ R implies A_2\
                  A_2 implies A_1$$







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited 4 hours ago

























                  answered 4 hours ago









                  MarianDMarianD

                  268128




                  268128











                  • $begingroup$
                    why not the reverse? why not have the current going into the resistor and then determining the voltage?
                    $endgroup$
                    – Ubaid Hassan
                    3 hours ago










                  • $begingroup$
                    Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                    $endgroup$
                    – MarianD
                    2 hours ago











                  • $begingroup$
                    @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                    $endgroup$
                    – Ubaid Hassan
                    34 mins ago
















                  • $begingroup$
                    why not the reverse? why not have the current going into the resistor and then determining the voltage?
                    $endgroup$
                    – Ubaid Hassan
                    3 hours ago










                  • $begingroup$
                    Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                    $endgroup$
                    – MarianD
                    2 hours ago











                  • $begingroup$
                    @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                    $endgroup$
                    – Jahan Claes
                    2 hours ago










                  • $begingroup$
                    I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                    $endgroup$
                    – Ubaid Hassan
                    34 mins ago















                  $begingroup$
                  why not the reverse? why not have the current going into the resistor and then determining the voltage?
                  $endgroup$
                  – Ubaid Hassan
                  3 hours ago




                  $begingroup$
                  why not the reverse? why not have the current going into the resistor and then determining the voltage?
                  $endgroup$
                  – Ubaid Hassan
                  3 hours ago












                  $begingroup$
                  Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                  $endgroup$
                  – MarianD
                  2 hours ago





                  $begingroup$
                  Imagine yourself the voltage as a force, the resistor as a body (mass), and the current as a resulting motion (acceleration). It's not possible accelerate the body without the force, the force is necessary condition for the acceleration. Similarly, there is no current without a voltage, the voltage is the basis. Your battery has a voltage without a current - if you connect the poles with a conductor, you enable the current to flow. The voltage is a constant, the amount of the current accommodates to the impedance.
                  $endgroup$
                  – MarianD
                  2 hours ago













                  $begingroup$
                  @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                  $endgroup$
                  – Jahan Claes
                  2 hours ago




                  $begingroup$
                  @UbaidHassan Another way to think about this is: The power plant makes it their job to ensure constant voltage, not constant current. They do this by adjusting how much power leaves the plant. If you try to draw more current, they burn more coal (or whatever). So why does voltage determine the current, and not vice versa? Because the power plant does its best to ensure voltage remains constant no matter how much current you draw.
                  $endgroup$
                  – Jahan Claes
                  2 hours ago












                  $begingroup$
                  @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                  $endgroup$
                  – Jahan Claes
                  2 hours ago




                  $begingroup$
                  @UbaidHassan The power plant isn't sending you a fixed chunk of energy. It's TRYING to send you a fixed chunk of voltage; the energy just comes along for the ride.
                  $endgroup$
                  – Jahan Claes
                  2 hours ago












                  $begingroup$
                  I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                  $endgroup$
                  – Ubaid Hassan
                  34 mins ago




                  $begingroup$
                  I just had an Aha! moment. thanks guys I finally understand that voltage is a constant whereas current varies with resistance :D
                  $endgroup$
                  – Ubaid Hassan
                  34 mins ago











                  0












                  $begingroup$

                  Most power sources have a fixed voltage (batteries, phone chargers, wall sockets) and can provide up to a certain limit amperes of current.



                  Phone chargers: always provide 5V, some are able to provide up to 2A while others can provide only 1A. The phone is responsible to "negotiate" with the charger how much current it draws so it doesn't damage the charger.



                  Wall sockets: always provide 230V AC (in Germany), but how much current is drawn depends on the connected device. Very little will be drawn by a phone charger, far more by a vacuum cleaner or an electric heater. Circuit breakers are in place that limit the current to 16A (usually) to prevent overheating wires.



                  So remember:



                  • Voltage is a property of a electrical source.

                  • Current will depend on the connected device(s)

                  Usually, if a device is connected to a variable voltage source, a higher voltage leads to a higher current. That is why high voltages are dangerous.






                  share|cite|improve this answer









                  $endgroup$

















                    0












                    $begingroup$

                    Most power sources have a fixed voltage (batteries, phone chargers, wall sockets) and can provide up to a certain limit amperes of current.



                    Phone chargers: always provide 5V, some are able to provide up to 2A while others can provide only 1A. The phone is responsible to "negotiate" with the charger how much current it draws so it doesn't damage the charger.



                    Wall sockets: always provide 230V AC (in Germany), but how much current is drawn depends on the connected device. Very little will be drawn by a phone charger, far more by a vacuum cleaner or an electric heater. Circuit breakers are in place that limit the current to 16A (usually) to prevent overheating wires.



                    So remember:



                    • Voltage is a property of a electrical source.

                    • Current will depend on the connected device(s)

                    Usually, if a device is connected to a variable voltage source, a higher voltage leads to a higher current. That is why high voltages are dangerous.






                    share|cite|improve this answer









                    $endgroup$















                      0












                      0








                      0





                      $begingroup$

                      Most power sources have a fixed voltage (batteries, phone chargers, wall sockets) and can provide up to a certain limit amperes of current.



                      Phone chargers: always provide 5V, some are able to provide up to 2A while others can provide only 1A. The phone is responsible to "negotiate" with the charger how much current it draws so it doesn't damage the charger.



                      Wall sockets: always provide 230V AC (in Germany), but how much current is drawn depends on the connected device. Very little will be drawn by a phone charger, far more by a vacuum cleaner or an electric heater. Circuit breakers are in place that limit the current to 16A (usually) to prevent overheating wires.



                      So remember:



                      • Voltage is a property of a electrical source.

                      • Current will depend on the connected device(s)

                      Usually, if a device is connected to a variable voltage source, a higher voltage leads to a higher current. That is why high voltages are dangerous.






                      share|cite|improve this answer









                      $endgroup$



                      Most power sources have a fixed voltage (batteries, phone chargers, wall sockets) and can provide up to a certain limit amperes of current.



                      Phone chargers: always provide 5V, some are able to provide up to 2A while others can provide only 1A. The phone is responsible to "negotiate" with the charger how much current it draws so it doesn't damage the charger.



                      Wall sockets: always provide 230V AC (in Germany), but how much current is drawn depends on the connected device. Very little will be drawn by a phone charger, far more by a vacuum cleaner or an electric heater. Circuit breakers are in place that limit the current to 16A (usually) to prevent overheating wires.



                      So remember:



                      • Voltage is a property of a electrical source.

                      • Current will depend on the connected device(s)

                      Usually, if a device is connected to a variable voltage source, a higher voltage leads to a higher current. That is why high voltages are dangerous.







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered 3 hours ago









                      JasperJasper

                      1,2521517




                      1,2521517





















                          0












                          $begingroup$

                          When you get a shock, the current is tiny. Only a few mA. You don't put much of a load on your household system. It is not like the lights in the house dim or anything. So the current capacity of the wires in the house is not really the issue.



                          But the higher the voltage, the more current flows through your body. If you get a 10mA shock from 120V, then you would get a 20mA shock from 240V. The sensation of being shocked, and the risk of permanent harm, are both related to the amount of current flowing. Greater current is more unpleasant, and ultimately greater risk of harm or death.






                          share|cite|improve this answer








                          New contributor




                          mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.






                          $endgroup$

















                            0












                            $begingroup$

                            When you get a shock, the current is tiny. Only a few mA. You don't put much of a load on your household system. It is not like the lights in the house dim or anything. So the current capacity of the wires in the house is not really the issue.



                            But the higher the voltage, the more current flows through your body. If you get a 10mA shock from 120V, then you would get a 20mA shock from 240V. The sensation of being shocked, and the risk of permanent harm, are both related to the amount of current flowing. Greater current is more unpleasant, and ultimately greater risk of harm or death.






                            share|cite|improve this answer








                            New contributor




                            mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






                            $endgroup$















                              0












                              0








                              0





                              $begingroup$

                              When you get a shock, the current is tiny. Only a few mA. You don't put much of a load on your household system. It is not like the lights in the house dim or anything. So the current capacity of the wires in the house is not really the issue.



                              But the higher the voltage, the more current flows through your body. If you get a 10mA shock from 120V, then you would get a 20mA shock from 240V. The sensation of being shocked, and the risk of permanent harm, are both related to the amount of current flowing. Greater current is more unpleasant, and ultimately greater risk of harm or death.






                              share|cite|improve this answer








                              New contributor




                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.






                              $endgroup$



                              When you get a shock, the current is tiny. Only a few mA. You don't put much of a load on your household system. It is not like the lights in the house dim or anything. So the current capacity of the wires in the house is not really the issue.



                              But the higher the voltage, the more current flows through your body. If you get a 10mA shock from 120V, then you would get a 20mA shock from 240V. The sensation of being shocked, and the risk of permanent harm, are both related to the amount of current flowing. Greater current is more unpleasant, and ultimately greater risk of harm or death.







                              share|cite|improve this answer








                              New contributor




                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              share|cite|improve this answer



                              share|cite|improve this answer






                              New contributor




                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              answered 3 hours ago









                              mkeithmkeith

                              1012




                              1012




                              New contributor




                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





                              New contributor





                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.






                              mkeith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





















                                  0












                                  $begingroup$

                                  When electrical engineers work on circuits that transfer energy, the characteristic they use is called "impedance". To get power moved most efficiently, they "match" the impedances. There's a wikipedia article: https://en.wikipedia.org/wiki/Impedance_matching



                                  Now impedance is simply the R in V=IR so we can compute the impedances for high and low voltage power and compare them with the impedance of a human.



                                  Keeping the power at 2.4KW, let's compare 120 and 240V:



                                  120V 20A => 6 ohms
                                  240V 10A => 24 ohms



                                  Note that the impedance was much higher with the higher voltage.



                                  And what is the impedance of a human? The first hit on DuckDuckGo for me is a Fluke article:



                                  "Human impedance variability has been shown to vary from 25 ohms to 180 ohms"
                                  https://support.fluke.com/biomedical/download/asset/ppp085_impedance_educational.pdf



                                  So we see that when shocking humans, our impedances will match better (and the shock will include more power) if we have the higher voltage.






                                  share|cite|improve this answer









                                  $endgroup$

















                                    0












                                    $begingroup$

                                    When electrical engineers work on circuits that transfer energy, the characteristic they use is called "impedance". To get power moved most efficiently, they "match" the impedances. There's a wikipedia article: https://en.wikipedia.org/wiki/Impedance_matching



                                    Now impedance is simply the R in V=IR so we can compute the impedances for high and low voltage power and compare them with the impedance of a human.



                                    Keeping the power at 2.4KW, let's compare 120 and 240V:



                                    120V 20A => 6 ohms
                                    240V 10A => 24 ohms



                                    Note that the impedance was much higher with the higher voltage.



                                    And what is the impedance of a human? The first hit on DuckDuckGo for me is a Fluke article:



                                    "Human impedance variability has been shown to vary from 25 ohms to 180 ohms"
                                    https://support.fluke.com/biomedical/download/asset/ppp085_impedance_educational.pdf



                                    So we see that when shocking humans, our impedances will match better (and the shock will include more power) if we have the higher voltage.






                                    share|cite|improve this answer









                                    $endgroup$















                                      0












                                      0








                                      0





                                      $begingroup$

                                      When electrical engineers work on circuits that transfer energy, the characteristic they use is called "impedance". To get power moved most efficiently, they "match" the impedances. There's a wikipedia article: https://en.wikipedia.org/wiki/Impedance_matching



                                      Now impedance is simply the R in V=IR so we can compute the impedances for high and low voltage power and compare them with the impedance of a human.



                                      Keeping the power at 2.4KW, let's compare 120 and 240V:



                                      120V 20A => 6 ohms
                                      240V 10A => 24 ohms



                                      Note that the impedance was much higher with the higher voltage.



                                      And what is the impedance of a human? The first hit on DuckDuckGo for me is a Fluke article:



                                      "Human impedance variability has been shown to vary from 25 ohms to 180 ohms"
                                      https://support.fluke.com/biomedical/download/asset/ppp085_impedance_educational.pdf



                                      So we see that when shocking humans, our impedances will match better (and the shock will include more power) if we have the higher voltage.






                                      share|cite|improve this answer









                                      $endgroup$



                                      When electrical engineers work on circuits that transfer energy, the characteristic they use is called "impedance". To get power moved most efficiently, they "match" the impedances. There's a wikipedia article: https://en.wikipedia.org/wiki/Impedance_matching



                                      Now impedance is simply the R in V=IR so we can compute the impedances for high and low voltage power and compare them with the impedance of a human.



                                      Keeping the power at 2.4KW, let's compare 120 and 240V:



                                      120V 20A => 6 ohms
                                      240V 10A => 24 ohms



                                      Note that the impedance was much higher with the higher voltage.



                                      And what is the impedance of a human? The first hit on DuckDuckGo for me is a Fluke article:



                                      "Human impedance variability has been shown to vary from 25 ohms to 180 ohms"
                                      https://support.fluke.com/biomedical/download/asset/ppp085_impedance_educational.pdf



                                      So we see that when shocking humans, our impedances will match better (and the shock will include more power) if we have the higher voltage.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered 17 mins ago









                                      Carl BrannenCarl Brannen

                                      9,67353067




                                      9,67353067




















                                          Ubaid Hassan is a new contributor. Be nice, and check out our Code of Conduct.









                                          draft saved

                                          draft discarded


















                                          Ubaid Hassan is a new contributor. Be nice, and check out our Code of Conduct.












                                          Ubaid Hassan is a new contributor. Be nice, and check out our Code of Conduct.











                                          Ubaid Hassan is a new contributor. Be nice, and check out our Code of Conduct.














                                          Thanks for contributing an answer to Physics Stack Exchange!


                                          • Please be sure to answer the question. Provide details and share your research!

                                          But avoid


                                          • Asking for help, clarification, or responding to other answers.

                                          • Making statements based on opinion; back them up with references or personal experience.

                                          Use MathJax to format equations. MathJax reference.


                                          To learn more, see our tips on writing great answers.




                                          draft saved


                                          draft discarded














                                          StackExchange.ready(
                                          function ()
                                          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f472964%2fwhy-is-high-voltage-dangerous%23new-answer', 'question_page');

                                          );

                                          Post as a guest















                                          Required, but never shown





















































                                          Required, but never shown














                                          Required, but never shown












                                          Required, but never shown







                                          Required, but never shown

































                                          Required, but never shown














                                          Required, but never shown












                                          Required, but never shown







                                          Required, but never shown







                                          Popular posts from this blog

                                          Dapidodigma demeter Subspecies | Notae | Tabula navigationisDapidodigmaAfrotropical Butterflies: Lycaenidae - Subtribe IolainaAmplifica

                                          Constantinus Vanšenkin Nexus externi | Tabula navigationisБольшая российская энциклопедияAmplifica

                                          Gaius Norbanus Flaccus (consul 38 a.C.n.) Index De gente | De cursu honorum | Notae | Fontes | Si vis plura legere | Tabula navigationisHic legere potes