Calculus II Professor will not accept my correct integral evaluation that uses a different method, should I bring this up further?Are there two answers to this integral problem?Help with understanding the solution to a volume of a solid $y = x, y = 0, x = 4, x = 7$ about $x = 1$Evaluate the Line IntegralRelated Rates- Expanding CircleEvaluating area using an integral in polar coordinatesWithout solving directly for the integral, decide if the value of the integral is positve or negative.Contour integral of $int_gamma fraczsin zdz$Evaluating integral $iint_D 2x-y ,dA$ bounded by circle of a given radiusArea of a square equivelent to that of a circle utilizing caclulusFinding the volume of a solid s using cross sections
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Calculus II Professor will not accept my correct integral evaluation that uses a different method, should I bring this up further?
Are there two answers to this integral problem?Help with understanding the solution to a volume of a solid $y = x, y = 0, x = 4, x = 7$ about $x = 1$Evaluate the Line IntegralRelated Rates- Expanding CircleEvaluating area using an integral in polar coordinatesWithout solving directly for the integral, decide if the value of the integral is positve or negative.Contour integral of $int_gamma fraczsin zdz$Evaluating integral $iint_D 2x-y ,dA$ bounded by circle of a given radiusArea of a square equivelent to that of a circle utilizing caclulusFinding the volume of a solid s using cross sections
$begingroup$
I am a freshman enrolled at an American University. Recently, I took an examination in which the following problem appeared:
Evaluate the following integral:
$int_0^4sqrt16-x^2dx$
My answer: 4$pi$, was correct. However, I received reduced credit for this answer because I did not solve it correctly (according to the professor). The exams are time-limited and have a fair amount of content, so when I saw this problem, I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
The context of the test was surrounding our unit on inverse trigonometry and integration by parts. This section of the test did not list any other instructions besides evaluating the definite integrals. I've talked to my professor about it and his only response was that I solved it wrong:
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Is my interpretation of evaluating the integral different? Does the instruction "Find the antiderivative and then evaluate" not need to exist for that to be required?
Thank you.
calculus integration
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
|
show 2 more comments
$begingroup$
I am a freshman enrolled at an American University. Recently, I took an examination in which the following problem appeared:
Evaluate the following integral:
$int_0^4sqrt16-x^2dx$
My answer: 4$pi$, was correct. However, I received reduced credit for this answer because I did not solve it correctly (according to the professor). The exams are time-limited and have a fair amount of content, so when I saw this problem, I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
The context of the test was surrounding our unit on inverse trigonometry and integration by parts. This section of the test did not list any other instructions besides evaluating the definite integrals. I've talked to my professor about it and his only response was that I solved it wrong:
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Is my interpretation of evaluating the integral different? Does the instruction "Find the antiderivative and then evaluate" not need to exist for that to be required?
Thank you.
calculus integration
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
you profesor in mixed up
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
can you post the exact problem question?
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
$endgroup$
– user146073
1 hour ago
$begingroup$
He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
$endgroup$
– herb steinberg
1 hour ago
$begingroup$
@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
$endgroup$
– user146073
1 hour ago
|
show 2 more comments
$begingroup$
I am a freshman enrolled at an American University. Recently, I took an examination in which the following problem appeared:
Evaluate the following integral:
$int_0^4sqrt16-x^2dx$
My answer: 4$pi$, was correct. However, I received reduced credit for this answer because I did not solve it correctly (according to the professor). The exams are time-limited and have a fair amount of content, so when I saw this problem, I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
The context of the test was surrounding our unit on inverse trigonometry and integration by parts. This section of the test did not list any other instructions besides evaluating the definite integrals. I've talked to my professor about it and his only response was that I solved it wrong:
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Is my interpretation of evaluating the integral different? Does the instruction "Find the antiderivative and then evaluate" not need to exist for that to be required?
Thank you.
calculus integration
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am a freshman enrolled at an American University. Recently, I took an examination in which the following problem appeared:
Evaluate the following integral:
$int_0^4sqrt16-x^2dx$
My answer: 4$pi$, was correct. However, I received reduced credit for this answer because I did not solve it correctly (according to the professor). The exams are time-limited and have a fair amount of content, so when I saw this problem, I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
The context of the test was surrounding our unit on inverse trigonometry and integration by parts. This section of the test did not list any other instructions besides evaluating the definite integrals. I've talked to my professor about it and his only response was that I solved it wrong:
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Is my interpretation of evaluating the integral different? Does the instruction "Find the antiderivative and then evaluate" not need to exist for that to be required?
Thank you.
calculus integration
calculus integration
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
user146073user146073
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
user146073user146073
161
asked 1 hour ago
user146073user146073
161
161
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user146073 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
you profesor in mixed up
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
can you post the exact problem question?
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
$endgroup$
– user146073
1 hour ago
$begingroup$
He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
$endgroup$
– herb steinberg
1 hour ago
$begingroup$
@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
$endgroup$
– user146073
1 hour ago
|
show 2 more comments
$begingroup$
you profesor in mixed up
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
can you post the exact problem question?
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
$endgroup$
– user146073
1 hour ago
$begingroup$
He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
$endgroup$
– herb steinberg
1 hour ago
$begingroup$
@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
$endgroup$
– user146073
1 hour ago
$begingroup$
you profesor in mixed up
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
you profesor in mixed up
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
can you post the exact problem question?
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
can you post the exact problem question?
$endgroup$
– Mikey Spivak
1 hour ago
$begingroup$
@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
$endgroup$
– user146073
1 hour ago
$begingroup$
@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
$endgroup$
– user146073
1 hour ago
$begingroup$
He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
$endgroup$
– herb steinberg
1 hour ago
$begingroup$
He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
$endgroup$
– herb steinberg
1 hour ago
$begingroup$
@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
$endgroup$
– user146073
1 hour ago
$begingroup$
@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
$endgroup$
– user146073
1 hour ago
|
show 2 more comments
4 Answers
4
active
oldest
votes
$begingroup$
An argument could be made that you should include a proof that the integral evaluates the area of a half-disk, rather than just asserting the answer.
Whether you “should” have gotten full points is more a matter of pedagogy than of mathematics, but as a practical tip: using (correct) method Y to solve a problem with instructions to use method X (especially in an intro class and when you are not familiar with the instructor and their teaching philosophy) is always a gamble.
answered 55 mins ago
user7530user7530
34.9k761113
$endgroup$
add a comment |
$begingroup$
As a student who has had a similar thing happen and heard of it happening to others, my personal recommendation would be to not bring it up again, it will probably be a losing battle. :(
But I would not consider your method "wrong" or "incorrect." There are many ways to solve a problem, you simply just made use of one of them, that wasn't the desired one.
As long as you explained how you came to your answer, the reason why your professor $textitprobably$ marked you down is that based on the class and section the test covered, the question was designed so that you would display and make use of your knowledge of trig substitution to solve the problem.
I would hope your professor didn't take too many points off (since the method does work), but in these classes you will usually be expected to give the professor a specific method that they are looking for.
answered 1 hour ago
HotdogHotdog
627
$endgroup$
add a comment |
$begingroup$
I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
Did you write this clearly in your test (as you did here)? If not, it is fair to give reduced points. One should always explain where answers come from. If yes, proceed reading.
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Do the instructions clearly disallow your solution? If not, it was not fair to you, and you should insist on it. If yes, read further.
Were these instructions available a priori, or they were included in the test itself? If available a priori, you should have complained about them before the test. If not, the instructions are unfair, and you should try to insist about it as well.
Also, recall that most of this is up to the professor, so you might be with bad luck, sadly.
answered 39 mins ago
Pedro APedro A
2,0461827
$endgroup$
add a comment |
$begingroup$
I've done some undergraduate teaching and my policy is always if you get the correct answer by any means then you get full credit, but others have different policies and it's really up to them.
You could argue your case. Your professor could argue back that solving the integral by trig substitution does not require the formula $A = pi r^2$, and he did not permit the use of that formula. He could argue that using that formula entails circular reasoning (the formula for the area of a circle has to be gotten by some limiting or integration method equivalent to evaluating $int_-r^r sqrtr^2-x^2dx$).
It could go either way for you. But I think it would be a waste of your and your professor's time.
answered 26 mins ago
D_SD_S
13.8k61552
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
An argument could be made that you should include a proof that the integral evaluates the area of a half-disk, rather than just asserting the answer.
Whether you “should” have gotten full points is more a matter of pedagogy than of mathematics, but as a practical tip: using (correct) method Y to solve a problem with instructions to use method X (especially in an intro class and when you are not familiar with the instructor and their teaching philosophy) is always a gamble.
answered 55 mins ago
user7530user7530
34.9k761113
$endgroup$
add a comment |
$begingroup$
An argument could be made that you should include a proof that the integral evaluates the area of a half-disk, rather than just asserting the answer.
Whether you “should” have gotten full points is more a matter of pedagogy than of mathematics, but as a practical tip: using (correct) method Y to solve a problem with instructions to use method X (especially in an intro class and when you are not familiar with the instructor and their teaching philosophy) is always a gamble.
answered 55 mins ago
user7530user7530
34.9k761113
$endgroup$
add a comment |
$begingroup$
An argument could be made that you should include a proof that the integral evaluates the area of a half-disk, rather than just asserting the answer.
Whether you “should” have gotten full points is more a matter of pedagogy than of mathematics, but as a practical tip: using (correct) method Y to solve a problem with instructions to use method X (especially in an intro class and when you are not familiar with the instructor and their teaching philosophy) is always a gamble.
answered 55 mins ago
user7530user7530
34.9k761113
$endgroup$
An argument could be made that you should include a proof that the integral evaluates the area of a half-disk, rather than just asserting the answer.
Whether you “should” have gotten full points is more a matter of pedagogy than of mathematics, but as a practical tip: using (correct) method Y to solve a problem with instructions to use method X (especially in an intro class and when you are not familiar with the instructor and their teaching philosophy) is always a gamble.
answered 55 mins ago
user7530user7530
34.9k761113
answered 55 mins ago
user7530user7530
34.9k761113
answered 55 mins ago
user7530user7530
34.9k761113
answered 55 mins ago
user7530user7530
34.9k761113
34.9k761113
add a comment |
add a comment |
$begingroup$
As a student who has had a similar thing happen and heard of it happening to others, my personal recommendation would be to not bring it up again, it will probably be a losing battle. :(
But I would not consider your method "wrong" or "incorrect." There are many ways to solve a problem, you simply just made use of one of them, that wasn't the desired one.
As long as you explained how you came to your answer, the reason why your professor $textitprobably$ marked you down is that based on the class and section the test covered, the question was designed so that you would display and make use of your knowledge of trig substitution to solve the problem.
I would hope your professor didn't take too many points off (since the method does work), but in these classes you will usually be expected to give the professor a specific method that they are looking for.
answered 1 hour ago
HotdogHotdog
627
$endgroup$
add a comment |
$begingroup$
As a student who has had a similar thing happen and heard of it happening to others, my personal recommendation would be to not bring it up again, it will probably be a losing battle. :(
But I would not consider your method "wrong" or "incorrect." There are many ways to solve a problem, you simply just made use of one of them, that wasn't the desired one.
As long as you explained how you came to your answer, the reason why your professor $textitprobably$ marked you down is that based on the class and section the test covered, the question was designed so that you would display and make use of your knowledge of trig substitution to solve the problem.
I would hope your professor didn't take too many points off (since the method does work), but in these classes you will usually be expected to give the professor a specific method that they are looking for.
answered 1 hour ago
HotdogHotdog
627
$endgroup$
add a comment |
$begingroup$
As a student who has had a similar thing happen and heard of it happening to others, my personal recommendation would be to not bring it up again, it will probably be a losing battle. :(
But I would not consider your method "wrong" or "incorrect." There are many ways to solve a problem, you simply just made use of one of them, that wasn't the desired one.
As long as you explained how you came to your answer, the reason why your professor $textitprobably$ marked you down is that based on the class and section the test covered, the question was designed so that you would display and make use of your knowledge of trig substitution to solve the problem.
I would hope your professor didn't take too many points off (since the method does work), but in these classes you will usually be expected to give the professor a specific method that they are looking for.
answered 1 hour ago
HotdogHotdog
627
$endgroup$
As a student who has had a similar thing happen and heard of it happening to others, my personal recommendation would be to not bring it up again, it will probably be a losing battle. :(
But I would not consider your method "wrong" or "incorrect." There are many ways to solve a problem, you simply just made use of one of them, that wasn't the desired one.
As long as you explained how you came to your answer, the reason why your professor $textitprobably$ marked you down is that based on the class and section the test covered, the question was designed so that you would display and make use of your knowledge of trig substitution to solve the problem.
I would hope your professor didn't take too many points off (since the method does work), but in these classes you will usually be expected to give the professor a specific method that they are looking for.
answered 1 hour ago
HotdogHotdog
627
answered 1 hour ago
HotdogHotdog
627
answered 1 hour ago
HotdogHotdog
627
answered 1 hour ago
HotdogHotdog
627
627
add a comment |
add a comment |
$begingroup$
I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
Did you write this clearly in your test (as you did here)? If not, it is fair to give reduced points. One should always explain where answers come from. If yes, proceed reading.
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Do the instructions clearly disallow your solution? If not, it was not fair to you, and you should insist on it. If yes, read further.
Were these instructions available a priori, or they were included in the test itself? If available a priori, you should have complained about them before the test. If not, the instructions are unfair, and you should try to insist about it as well.
Also, recall that most of this is up to the professor, so you might be with bad luck, sadly.
answered 39 mins ago
Pedro APedro A
2,0461827
$endgroup$
add a comment |
$begingroup$
I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
Did you write this clearly in your test (as you did here)? If not, it is fair to give reduced points. One should always explain where answers come from. If yes, proceed reading.
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Do the instructions clearly disallow your solution? If not, it was not fair to you, and you should insist on it. If yes, read further.
Were these instructions available a priori, or they were included in the test itself? If available a priori, you should have complained about them before the test. If not, the instructions are unfair, and you should try to insist about it as well.
Also, recall that most of this is up to the professor, so you might be with bad luck, sadly.
answered 39 mins ago
Pedro APedro A
2,0461827
$endgroup$
add a comment |
$begingroup$
I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
Did you write this clearly in your test (as you did here)? If not, it is fair to give reduced points. One should always explain where answers come from. If yes, proceed reading.
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Do the instructions clearly disallow your solution? If not, it was not fair to you, and you should insist on it. If yes, read further.
Were these instructions available a priori, or they were included in the test itself? If available a priori, you should have complained about them before the test. If not, the instructions are unfair, and you should try to insist about it as well.
Also, recall that most of this is up to the professor, so you might be with bad luck, sadly.
answered 39 mins ago
Pedro APedro A
2,0461827
$endgroup$
I noticed it was the equation of the top half of a circle centered at (0, 0) and with radius 4. Knowing this, and my knowledge of the integral indicating the signed area under a curve, I merely took the area of a quarter-circle of radius 4, $frac14$$pi$$r^2$ and wrote my answer of 4$pi$.
Did you write this clearly in your test (as you did here)? If not, it is fair to give reduced points. One should always explain where answers come from. If yes, proceed reading.
To receive full credit, you would have had to evaluate an integral, as the instructions indicated.
Do the instructions clearly disallow your solution? If not, it was not fair to you, and you should insist on it. If yes, read further.
Were these instructions available a priori, or they were included in the test itself? If available a priori, you should have complained about them before the test. If not, the instructions are unfair, and you should try to insist about it as well.
Also, recall that most of this is up to the professor, so you might be with bad luck, sadly.
answered 39 mins ago
Pedro APedro A
2,0461827
answered 39 mins ago
Pedro APedro A
2,0461827
answered 39 mins ago
Pedro APedro A
2,0461827
answered 39 mins ago
Pedro APedro A
2,0461827
2,0461827
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I've done some undergraduate teaching and my policy is always if you get the correct answer by any means then you get full credit, but others have different policies and it's really up to them.
You could argue your case. Your professor could argue back that solving the integral by trig substitution does not require the formula $A = pi r^2$, and he did not permit the use of that formula. He could argue that using that formula entails circular reasoning (the formula for the area of a circle has to be gotten by some limiting or integration method equivalent to evaluating $int_-r^r sqrtr^2-x^2dx$).
It could go either way for you. But I think it would be a waste of your and your professor's time.
answered 26 mins ago
D_SD_S
13.8k61552
$endgroup$
add a comment |
$begingroup$
I've done some undergraduate teaching and my policy is always if you get the correct answer by any means then you get full credit, but others have different policies and it's really up to them.
You could argue your case. Your professor could argue back that solving the integral by trig substitution does not require the formula $A = pi r^2$, and he did not permit the use of that formula. He could argue that using that formula entails circular reasoning (the formula for the area of a circle has to be gotten by some limiting or integration method equivalent to evaluating $int_-r^r sqrtr^2-x^2dx$).
It could go either way for you. But I think it would be a waste of your and your professor's time.
answered 26 mins ago
D_SD_S
13.8k61552
$endgroup$
add a comment |
$begingroup$
I've done some undergraduate teaching and my policy is always if you get the correct answer by any means then you get full credit, but others have different policies and it's really up to them.
You could argue your case. Your professor could argue back that solving the integral by trig substitution does not require the formula $A = pi r^2$, and he did not permit the use of that formula. He could argue that using that formula entails circular reasoning (the formula for the area of a circle has to be gotten by some limiting or integration method equivalent to evaluating $int_-r^r sqrtr^2-x^2dx$).
It could go either way for you. But I think it would be a waste of your and your professor's time.
answered 26 mins ago
D_SD_S
13.8k61552
$endgroup$
I've done some undergraduate teaching and my policy is always if you get the correct answer by any means then you get full credit, but others have different policies and it's really up to them.
You could argue your case. Your professor could argue back that solving the integral by trig substitution does not require the formula $A = pi r^2$, and he did not permit the use of that formula. He could argue that using that formula entails circular reasoning (the formula for the area of a circle has to be gotten by some limiting or integration method equivalent to evaluating $int_-r^r sqrtr^2-x^2dx$).
It could go either way for you. But I think it would be a waste of your and your professor's time.
answered 26 mins ago
D_SD_S
13.8k61552
answered 26 mins ago
D_SD_S
13.8k61552
answered 26 mins ago
D_SD_S
13.8k61552
answered 26 mins ago
D_SD_S
13.8k61552
13.8k61552
add a comment |
add a comment |
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you profesor in mixed up
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– Mikey Spivak
1 hour ago
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can you post the exact problem question?
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– Mikey Spivak
1 hour ago
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@MikeySpivak The question sheet is no longer in my possession, but I remember exactly what it said "Evaluate the following integrals:" (there were several). I wrote the integral exactly as it appeared.
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– user146073
1 hour ago
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He was obviously nitpicking, since you were able to bypass a direct (tedious) evaluation, which is what he wanted.
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– herb steinberg
1 hour ago
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@herbsteinberg Would I be justified to go higher up in the math department with this? In a course where every point matters?
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– user146073
1 hour ago