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Visualizing the difference curve in a 2D plot?
Copying each object in a plot separately as an imageregion plot in a 2-simplexWhy is Chop ignored in Plot?How can I plot a 3-variables function to identify the neutral surface and a regionPlot a curve on a latticeHelp plot with horizontal fillingHow to improve this plot?Plot data with different confidence intervalsGetting the coordinates of a specific point out of a plotDifferent shades of the same colour in one plot
$begingroup$
I have two functions $f(x,y)$ and $g(x,y)$. I wish to perform two tasks on a 2-dimensional figure:
Plot the curve where each point satisfies $f(x,y)=g(x,y)$.
Mark one side of the curve with red.
I tried to use Plot3D like the following
myfunc[x_, y_]:= If[f[x, y] < g(x, y), 1,0];
Plot3D[myfunc[x, y], x, 0, 10, y, 0, 3]
It gives what I expected, but how can I do this in a 2D plot?
plotting
$endgroup$
add a comment |
$begingroup$
I have two functions $f(x,y)$ and $g(x,y)$. I wish to perform two tasks on a 2-dimensional figure:
Plot the curve where each point satisfies $f(x,y)=g(x,y)$.
Mark one side of the curve with red.
I tried to use Plot3D like the following
myfunc[x_, y_]:= If[f[x, y] < g(x, y), 1,0];
Plot3D[myfunc[x, y], x, 0, 10, y, 0, 3]
It gives what I expected, but how can I do this in a 2D plot?
plotting
$endgroup$
add a comment |
$begingroup$
I have two functions $f(x,y)$ and $g(x,y)$. I wish to perform two tasks on a 2-dimensional figure:
Plot the curve where each point satisfies $f(x,y)=g(x,y)$.
Mark one side of the curve with red.
I tried to use Plot3D like the following
myfunc[x_, y_]:= If[f[x, y] < g(x, y), 1,0];
Plot3D[myfunc[x, y], x, 0, 10, y, 0, 3]
It gives what I expected, but how can I do this in a 2D plot?
plotting
$endgroup$
I have two functions $f(x,y)$ and $g(x,y)$. I wish to perform two tasks on a 2-dimensional figure:
Plot the curve where each point satisfies $f(x,y)=g(x,y)$.
Mark one side of the curve with red.
I tried to use Plot3D like the following
myfunc[x_, y_]:= If[f[x, y] < g(x, y), 1,0];
Plot3D[myfunc[x, y], x, 0, 10, y, 0, 3]
It gives what I expected, but how can I do this in a 2D plot?
plotting
plotting
edited 53 mins ago
m_goldberg
87.7k872198
87.7k872198
asked 6 hours ago
David Xiaoyu XuDavid Xiaoyu Xu
244
244
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
RegionPlot[f[x, y] <= g[x, y], x, 0, 10, y, 0, 3]
$endgroup$
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
add a comment |
$begingroup$
ContourPlot[f[x, y] - g[x, y], x, 0, 10, y, 0, 3,
Contours -> 0, ContourShading -> None, Red]
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
RegionPlot[f[x, y] <= g[x, y], x, 0, 10, y, 0, 3]
$endgroup$
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
add a comment |
$begingroup$
RegionPlot[f[x, y] <= g[x, y], x, 0, 10, y, 0, 3]
$endgroup$
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
add a comment |
$begingroup$
RegionPlot[f[x, y] <= g[x, y], x, 0, 10, y, 0, 3]
$endgroup$
RegionPlot[f[x, y] <= g[x, y], x, 0, 10, y, 0, 3]
answered 6 hours ago
Henrik SchumacherHenrik Schumacher
57.3k577157
57.3k577157
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
add a comment |
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
$begingroup$
thanks! I didn't know this before.
$endgroup$
– David Xiaoyu Xu
6 hours ago
add a comment |
$begingroup$
ContourPlot[f[x, y] - g[x, y], x, 0, 10, y, 0, 3,
Contours -> 0, ContourShading -> None, Red]
$endgroup$
add a comment |
$begingroup$
ContourPlot[f[x, y] - g[x, y], x, 0, 10, y, 0, 3,
Contours -> 0, ContourShading -> None, Red]
$endgroup$
add a comment |
$begingroup$
ContourPlot[f[x, y] - g[x, y], x, 0, 10, y, 0, 3,
Contours -> 0, ContourShading -> None, Red]
$endgroup$
ContourPlot[f[x, y] - g[x, y], x, 0, 10, y, 0, 3,
Contours -> 0, ContourShading -> None, Red]
answered 6 hours ago
kglrkglr
189k10206424
189k10206424
add a comment |
add a comment |
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