Partitioning values in a sequenceOrdering the elements in a list and separate them into sublists for plottingFinding all partitions of a setPartitioning an image based on featuresPartition list into a given number of sub-listsPartitioning List Into Sublists of Length 2 With The Pairing Being RandomCluster numbers into n partitions so that each partitions sum is closest to total/nEfficient lazy weak compositionsTiming and memory use is critical:fast partitioning of binary sparse arrayVariable iterator in Do Loop (splitting a list)Non-Constant Partitioning of a List with Order AnalysisTotally orderless partition
A Note on N!
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Partitioning values in a sequence
Ordering the elements in a list and separate them into sublists for plottingFinding all partitions of a setPartitioning an image based on featuresPartition list into a given number of sub-listsPartitioning List Into Sublists of Length 2 With The Pairing Being RandomCluster numbers into n partitions so that each partitions sum is closest to total/nEfficient lazy weak compositionsTiming and memory use is critical:fast partitioning of binary sparse arrayVariable iterator in Do Loop (splitting a list)Non-Constant Partitioning of a List with Order AnalysisTotally orderless partition
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 51 secs ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
add a comment |
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 51 secs ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
$begingroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
edited 51 secs ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
$endgroup$
I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?
Here is the start of the sequence:
list = 2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197;
Thanks.
cheers,
Jamie
partitions
partitions
edited 51 secs ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
edited 51 secs ago
user64494
3,65311122
asked 5 hours ago
Jamie MJamie M
475
edited 51 secs ago
user64494
3,65311122
edited 51 secs ago
user64494
3,65311122
edited 51 secs ago
user64494
3,65311122
3,65311122
asked 5 hours ago
Jamie MJamie M
475
asked 5 hours ago
Jamie MJamie M
475
asked 5 hours ago
Jamie MJamie M
475
475
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
add a comment |
$begingroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
$endgroup$
You could for instance fit a mean polynomial function through the data:
fun = NonlinearModelFit[list, a x^2 + b x + c , a, b, c, x] //Normal
-48.3941 + 6.86017 x + 0.0161064 x^2
This will separarate the upper line from the lower line that you can see in the plot:
Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, x, 0, 125, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]
Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:
upperLine = ;
lowerLine = ;
Do[
If[list[[x]] > fun,
AppendTo[upperLine, x, list[[x]]],
AppendTo[lowerLine, x, list[[x]]]];
, x, 1, Length[list]]
The upperLine and lowerLine data sets then look like:
ListLinePlot[upperLine], ListLinePlot[lowerLine]
Repeat the process on the lowerLine data to separate the sequences further.
answered 5 hours ago
KagaratschKagaratsch
4,87531348
edited 4 hours ago
answered 5 hours ago
KagaratschKagaratsch
4,87531348
answered 5 hours ago
KagaratschKagaratsch
4,87531348
answered 5 hours ago
KagaratschKagaratsch
4,87531348
4,87531348
add a comment |
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
add a comment |
$begingroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
$endgroup$
list = 2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19,
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197;
upper = FindPeaks[list];
lower = 1, -1 # & /@ FindPeaks[-list];
ListLinePlot[list, lower, upper,
PlotStyle -> LightGray, Blue, Red]
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
answered 59 mins ago
Bob HanlonBob Hanlon
61.9k33598
61.9k33598
add a comment |
add a comment |
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$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
5 hours ago