What is ls Largest Number Formed by only moving two sticks in 508? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Largest number with five 1's and five numeric operations90s Number PuzzleWhat is the largest number you can create with 0000 by moving only two sticks?Make numbers 1 - 32 using the digits 2, 0, 1, 7Yet another matchstick puzzleMathematical riddleMake numbers 1 - 30 using the digits 2, 0, 1, 8Four points with only two distancesCreate Numbers 1 - 100 using 1,9,6,8Find 108 by using 3,4,6
Marquee sign letters
When speaking, how do you change your mind mid-sentence?
Not within Jobscope - Aggravated injury
When does Bran Stark remember Jamie pushing him?
All ASCII characters with a given bit count
Why did Israel vote against lifting the American embargo on Cuba?
What happened to Viserion in Season 7?
How would it unbalance gameplay to rule that Weapon Master allows for picking a fighting style?
Feather, the Redeemed and Dire Fleet Daredevil
Are there existing rules/lore for MTG planeswalkers?
false 'Security alert' from Google - every login generates mails from 'no-reply@accounts.google.com'
Deciphering death certificate writing
/bin/ls sorts differently than just ls
Does using the Inspiration rules for character defects encourage My Guy Syndrome?
Calculating the expected value of truncated normal
What is the purpose of the side handle on a hand ("eggbeater") drill?
Is it OK if I do not take the receipt in Germany?
Why doesn't the university give past final exams' answers?
How to keep bees out of canned beverages?
Is Bran literally the world's memory?
What's called a person who work as someone who puts products on shelves in stores?
My admission is revoked after accepting the admission offer
When I export an AI 300x60 art board it saves with bigger dimensions
Is it appropriate to mention a relatable company blog post when you're asked about the company?
What is ls Largest Number Formed by only moving two sticks in 508?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Largest number with five 1's and five numeric operations90s Number PuzzleWhat is the largest number you can create with 0000 by moving only two sticks?Make numbers 1 - 32 using the digits 2, 0, 1, 7Yet another matchstick puzzleMathematical riddleMake numbers 1 - 30 using the digits 2, 0, 1, 8Four points with only two distancesCreate Numbers 1 - 100 using 1,9,6,8Find 108 by using 3,4,6
$begingroup$
Tilting the Image is not allowed.
You can cannot change order of digits.
You cannot change the Size if Digits unless you are harry potter.
You can increase or decrease space between digits though.
Hint:Think different
mathematics matches
asked 1 hour ago
AmanSharmaAmanSharma
1364
$endgroup$
add a comment |
$begingroup$
Tilting the Image is not allowed.
You can cannot change order of digits.
You cannot change the Size if Digits unless you are harry potter.
You can increase or decrease space between digits though.
Hint:Think different
mathematics matches
asked 1 hour ago
AmanSharmaAmanSharma
1364
$endgroup$
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago
add a comment |
$begingroup$
Tilting the Image is not allowed.
You can cannot change order of digits.
You cannot change the Size if Digits unless you are harry potter.
You can increase or decrease space between digits though.
Hint:Think different
mathematics matches
asked 1 hour ago
AmanSharmaAmanSharma
1364
$endgroup$
Tilting the Image is not allowed.
You can cannot change order of digits.
You cannot change the Size if Digits unless you are harry potter.
You can increase or decrease space between digits though.
Hint:Think different
mathematics matches
mathematics matches
asked 1 hour ago
AmanSharmaAmanSharma
1364
asked 1 hour ago
AmanSharmaAmanSharma
1364
edited 1 hour ago
AmanSharma
asked 1 hour ago
AmanSharmaAmanSharma
1364
asked 1 hour ago
AmanSharmaAmanSharma
1364
asked 1 hour ago
AmanSharmaAmanSharma
1364
1364
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago
add a comment |
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago
add a comment |
6 Answers
6
active
oldest
votes
$begingroup$
Slightly out of the box, but probably legal.
6E8, moving the two right sticks of the 0. 9E8 might be possible, but I don't think that's the accepted way of making a digital 9.
So far out of the box it's probably illegal.
g98 in Graham's Notation, where Graham's Number is g64.
answered 1 hour ago
SconibulusSconibulus
14.7k128101
$endgroup$
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
add a comment |
$begingroup$
Without taking too many liberties with the possibilities when it comes to rules...
I would say that the largest number made by moving only two sticks and without invoking any sort of exponents is:
15118 created by moving the top sticks from the zero to make a one in front of the 5...
answered 1 hour ago
Dr tDr t
1,248313
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
add a comment |
$begingroup$
Wisest answer:
a. $5118^11$
By removing the two sticks of the zero and placing them on exponent :p
Debatable:
b. $5$^$118$ $= 5^118$ by using the caret symbol
Still debatable, allowing different sizes:
c. $11^5118$
Allowing that digits can have different sizes
Extremely debatable solution:
d. $5118! ge 5^16762$
by cutting sticks
This solution could be acceptable for mathematicians' haters...
e. $56/0 longrightarrow +infty$, yes, the divide symbol is smaller than digits...
All of these solutions still remain if you can:
flip by 180° the sheet of paper (or your computer), and that is also a debatable action !
Which gives :
a. $8115^11$
b. $8$^$115$ $= 8^115$
c. $11^8115$
d. $8115!$
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
$endgroup$
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
|
show 6 more comments
$begingroup$
Without going too far out of the box:
15118 by removing the top and bottom matches from the 0 (creating 2 ones) and using them to create a one at the front
Actually, that should be:
51181 using the same method but putting the new digit at the end.
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
add a comment |
$begingroup$
Without adding extra digits and keeping with the digital-like format,
938
You can do this by
Removing the two matches on the left side of the zero and turning on horizontal to make the 0 a 3, and the other match to the top right of the 5 to turn it into a 9.
answered 1 hour ago
SensoraySensoray
4,54311246
$endgroup$
add a comment |
$begingroup$
Deleted - incorrect.
(And some random text to get > 30 characters!)
answered 8 mins ago
StilezStilez
1,224211
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "559"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f82110%2fwhat-is-ls-largest-number-formed-by-only-moving-two-sticks-in-508%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Slightly out of the box, but probably legal.
6E8, moving the two right sticks of the 0. 9E8 might be possible, but I don't think that's the accepted way of making a digital 9.
So far out of the box it's probably illegal.
g98 in Graham's Notation, where Graham's Number is g64.
answered 1 hour ago
SconibulusSconibulus
14.7k128101
$endgroup$
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
add a comment |
$begingroup$
Slightly out of the box, but probably legal.
6E8, moving the two right sticks of the 0. 9E8 might be possible, but I don't think that's the accepted way of making a digital 9.
So far out of the box it's probably illegal.
g98 in Graham's Notation, where Graham's Number is g64.
answered 1 hour ago
SconibulusSconibulus
14.7k128101
$endgroup$
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
add a comment |
$begingroup$
Slightly out of the box, but probably legal.
6E8, moving the two right sticks of the 0. 9E8 might be possible, but I don't think that's the accepted way of making a digital 9.
So far out of the box it's probably illegal.
g98 in Graham's Notation, where Graham's Number is g64.
answered 1 hour ago
SconibulusSconibulus
14.7k128101
$endgroup$
Slightly out of the box, but probably legal.
6E8, moving the two right sticks of the 0. 9E8 might be possible, but I don't think that's the accepted way of making a digital 9.
So far out of the box it's probably illegal.
g98 in Graham's Notation, where Graham's Number is g64.
answered 1 hour ago
SconibulusSconibulus
14.7k128101
edited 1 hour ago
answered 1 hour ago
SconibulusSconibulus
14.7k128101
answered 1 hour ago
SconibulusSconibulus
14.7k128101
answered 1 hour ago
SconibulusSconibulus
14.7k128101
14.7k128101
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
add a comment |
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
Legal But Still Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
$begingroup$
@AmanSharma Cheated a bit harder
$endgroup$
– Sconibulus
1 hour ago
5
5
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
$begingroup$
@AmanSharma: You realize you might not be talking to a "Bro" or to someone who doesn't like being called "Bro"?
$endgroup$
– Eric Duminil
41 mins ago
add a comment |
$begingroup$
Without taking too many liberties with the possibilities when it comes to rules...
I would say that the largest number made by moving only two sticks and without invoking any sort of exponents is:
15118 created by moving the top sticks from the zero to make a one in front of the 5...
answered 1 hour ago
Dr tDr t
1,248313
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
add a comment |
$begingroup$
Without taking too many liberties with the possibilities when it comes to rules...
I would say that the largest number made by moving only two sticks and without invoking any sort of exponents is:
15118 created by moving the top sticks from the zero to make a one in front of the 5...
answered 1 hour ago
Dr tDr t
1,248313
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
add a comment |
$begingroup$
Without taking too many liberties with the possibilities when it comes to rules...
I would say that the largest number made by moving only two sticks and without invoking any sort of exponents is:
15118 created by moving the top sticks from the zero to make a one in front of the 5...
answered 1 hour ago
Dr tDr t
1,248313
$endgroup$
Without taking too many liberties with the possibilities when it comes to rules...
I would say that the largest number made by moving only two sticks and without invoking any sort of exponents is:
15118 created by moving the top sticks from the zero to make a one in front of the 5...
answered 1 hour ago
Dr tDr t
1,248313
answered 1 hour ago
Dr tDr t
1,248313
answered 1 hour ago
Dr tDr t
1,248313
answered 1 hour ago
Dr tDr t
1,248313
1,248313
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
add a comment |
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
$begingroup$
You can place the one at the end. But I agree with @AmanSharma remains a sub-optimal solution
$endgroup$
– J.Khamphousone
46 mins ago
add a comment |
$begingroup$
Wisest answer:
a. $5118^11$
By removing the two sticks of the zero and placing them on exponent :p
Debatable:
b. $5$^$118$ $= 5^118$ by using the caret symbol
Still debatable, allowing different sizes:
c. $11^5118$
Allowing that digits can have different sizes
Extremely debatable solution:
d. $5118! ge 5^16762$
by cutting sticks
This solution could be acceptable for mathematicians' haters...
e. $56/0 longrightarrow +infty$, yes, the divide symbol is smaller than digits...
All of these solutions still remain if you can:
flip by 180° the sheet of paper (or your computer), and that is also a debatable action !
Which gives :
a. $8115^11$
b. $8$^$115$ $= 8^115$
c. $11^8115$
d. $8115!$
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
$endgroup$
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
|
show 6 more comments
$begingroup$
Wisest answer:
a. $5118^11$
By removing the two sticks of the zero and placing them on exponent :p
Debatable:
b. $5$^$118$ $= 5^118$ by using the caret symbol
Still debatable, allowing different sizes:
c. $11^5118$
Allowing that digits can have different sizes
Extremely debatable solution:
d. $5118! ge 5^16762$
by cutting sticks
This solution could be acceptable for mathematicians' haters...
e. $56/0 longrightarrow +infty$, yes, the divide symbol is smaller than digits...
All of these solutions still remain if you can:
flip by 180° the sheet of paper (or your computer), and that is also a debatable action !
Which gives :
a. $8115^11$
b. $8$^$115$ $= 8^115$
c. $11^8115$
d. $8115!$
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
$endgroup$
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
|
show 6 more comments
$begingroup$
Wisest answer:
a. $5118^11$
By removing the two sticks of the zero and placing them on exponent :p
Debatable:
b. $5$^$118$ $= 5^118$ by using the caret symbol
Still debatable, allowing different sizes:
c. $11^5118$
Allowing that digits can have different sizes
Extremely debatable solution:
d. $5118! ge 5^16762$
by cutting sticks
This solution could be acceptable for mathematicians' haters...
e. $56/0 longrightarrow +infty$, yes, the divide symbol is smaller than digits...
All of these solutions still remain if you can:
flip by 180° the sheet of paper (or your computer), and that is also a debatable action !
Which gives :
a. $8115^11$
b. $8$^$115$ $= 8^115$
c. $11^8115$
d. $8115!$
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
$endgroup$
Wisest answer:
a. $5118^11$
By removing the two sticks of the zero and placing them on exponent :p
Debatable:
b. $5$^$118$ $= 5^118$ by using the caret symbol
Still debatable, allowing different sizes:
c. $11^5118$
Allowing that digits can have different sizes
Extremely debatable solution:
d. $5118! ge 5^16762$
by cutting sticks
This solution could be acceptable for mathematicians' haters...
e. $56/0 longrightarrow +infty$, yes, the divide symbol is smaller than digits...
All of these solutions still remain if you can:
flip by 180° the sheet of paper (or your computer), and that is also a debatable action !
Which gives :
a. $8115^11$
b. $8$^$115$ $= 8^115$
c. $11^8115$
d. $8115!$
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
edited 8 mins ago
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
answered 1 hour ago
J.KhamphousoneJ.Khamphousone
2056
2056
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
|
show 6 more comments
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
1
1
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
That was out of universe . We are not changing size of digits here Bro. Also infinity isn't a number.
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I know ! That's why I wrote it's debetable, but my wisest answer still remains
$endgroup$
– J.Khamphousone
53 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
@AmanSharma I've added another debatable solution using the Caret Symbol
$endgroup$
– J.Khamphousone
50 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
$begingroup$
About infinity it was more of a joke rather than a solution ;p
$endgroup$
– J.Khamphousone
48 mins ago
1
1
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
$begingroup$
rot13(svsgl-avar bire mreb vf n ovttre vasvavgl guna svsgl-fvk bire mreb)
$endgroup$
– ielyamani
27 mins ago
|
show 6 more comments
$begingroup$
Without going too far out of the box:
15118 by removing the top and bottom matches from the 0 (creating 2 ones) and using them to create a one at the front
Actually, that should be:
51181 using the same method but putting the new digit at the end.
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
add a comment |
$begingroup$
Without going too far out of the box:
15118 by removing the top and bottom matches from the 0 (creating 2 ones) and using them to create a one at the front
Actually, that should be:
51181 using the same method but putting the new digit at the end.
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
$endgroup$
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
add a comment |
$begingroup$
Without going too far out of the box:
15118 by removing the top and bottom matches from the 0 (creating 2 ones) and using them to create a one at the front
Actually, that should be:
51181 using the same method but putting the new digit at the end.
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
$endgroup$
Without going too far out of the box:
15118 by removing the top and bottom matches from the 0 (creating 2 ones) and using them to create a one at the front
Actually, that should be:
51181 using the same method but putting the new digit at the end.
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
edited 1 hour ago
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
answered 1 hour ago
PugmonkeyPugmonkey
3,5901220
3,5901220
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
add a comment |
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
$begingroup$
Bro You are long long long long .... way behind the largest Number
$endgroup$
– AmanSharma
1 hour ago
add a comment |
$begingroup$
Without adding extra digits and keeping with the digital-like format,
938
You can do this by
Removing the two matches on the left side of the zero and turning on horizontal to make the 0 a 3, and the other match to the top right of the 5 to turn it into a 9.
answered 1 hour ago
SensoraySensoray
4,54311246
$endgroup$
add a comment |
$begingroup$
Without adding extra digits and keeping with the digital-like format,
938
You can do this by
Removing the two matches on the left side of the zero and turning on horizontal to make the 0 a 3, and the other match to the top right of the 5 to turn it into a 9.
answered 1 hour ago
SensoraySensoray
4,54311246
$endgroup$
add a comment |
$begingroup$
Without adding extra digits and keeping with the digital-like format,
938
You can do this by
Removing the two matches on the left side of the zero and turning on horizontal to make the 0 a 3, and the other match to the top right of the 5 to turn it into a 9.
answered 1 hour ago
SensoraySensoray
4,54311246
$endgroup$
Without adding extra digits and keeping with the digital-like format,
938
You can do this by
Removing the two matches on the left side of the zero and turning on horizontal to make the 0 a 3, and the other match to the top right of the 5 to turn it into a 9.
answered 1 hour ago
SensoraySensoray
4,54311246
answered 1 hour ago
SensoraySensoray
4,54311246
answered 1 hour ago
SensoraySensoray
4,54311246
answered 1 hour ago
SensoraySensoray
4,54311246
4,54311246
add a comment |
add a comment |
$begingroup$
Deleted - incorrect.
(And some random text to get > 30 characters!)
answered 8 mins ago
StilezStilez
1,224211
$endgroup$
add a comment |
$begingroup$
Deleted - incorrect.
(And some random text to get > 30 characters!)
answered 8 mins ago
StilezStilez
1,224211
$endgroup$
add a comment |
$begingroup$
Deleted - incorrect.
(And some random text to get > 30 characters!)
answered 8 mins ago
StilezStilez
1,224211
$endgroup$
Deleted - incorrect.
(And some random text to get > 30 characters!)
answered 8 mins ago
StilezStilez
1,224211
answered 8 mins ago
StilezStilez
1,224211
answered 8 mins ago
StilezStilez
1,224211
answered 8 mins ago
StilezStilez
1,224211
1,224211
add a comment |
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f82110%2fwhat-is-ls-largest-number-formed-by-only-moving-two-sticks-in-508%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
youtube.com/watch?v=9m6S0x-AKNU
$endgroup$
– ielyamani
31 mins ago