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How do I color the graph in datavisualization?

Color the faces of a graphHow to color vertices in a TikZ graph?How to change the following graph?How to color the area under a curve using tikz datavisualization?How to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Tikz and exponential style tick labelMaking a complete graph with one edge in diffrent colorMatching the text background color in tikz with the background color of a presentation slideWrite under the graphTikZ fill using draw color

2

MWE;

documentclass[tikz,border=10pt]standalone
usepackagetikz
usetikzlibrarydatavisualization
usetikzlibraryarrows,calc
usetikzlibraryshapes,positioning
usetikzlibrarydecorations.markings
usetikzlibrarydatavisualization.formats.functions
defmytypesetter#1
pgfmathparse#1/pi
pgfkeys/pgf/number format/precision=2
pgfmathroundtozerofillpgfmathresult
pgfmathifisintpgfmathresult
pgfmathprintnumberpgfmathresult$pi$

pgfmathprintnumber[/pgf/number format/frac, frac denom=2, frac whole=false]pgfmathresult$pi$


begindocument


begintikzpicture[>=latex]
datavisualization [
 school book axes, %scientific axes=clean,
 all axes=,
 x axis=
 label=$omega t$,
 ticks=
 step=(pi/2),
 tick typesetter/.code=mytypesetter##1,
 ,
 y axis=
 label=$v$, 
 ticks=none,
 ,
 style sheet=strong colors,
 style sheet=vary dashing,
 visualize as smooth line/.list=gerilim,
 gerilim=label in legend=text=$v$,
]
data [set=gerilim, format=function] 
 var x : interval [0:2*pi] samples 100;
 func y = 2*sin(value x r);
;
endtikzpicture 
enddocument

But that I want

.

How do I get this graph from my source code without using beginaxis[... endaxis?

tikz-pgf graphics tikz-shape tikz-decorations

share|improve this question

asked 2 hours ago

ÖzgürÖzgür

1,4421020

add a comment | 

2

MWE;

documentclass[tikz,border=10pt]standalone
usepackagetikz
usetikzlibrarydatavisualization
usetikzlibraryarrows,calc
usetikzlibraryshapes,positioning
usetikzlibrarydecorations.markings
usetikzlibrarydatavisualization.formats.functions
defmytypesetter#1
pgfmathparse#1/pi
pgfkeys/pgf/number format/precision=2
pgfmathroundtozerofillpgfmathresult
pgfmathifisintpgfmathresult
pgfmathprintnumberpgfmathresult$pi$

pgfmathprintnumber[/pgf/number format/frac, frac denom=2, frac whole=false]pgfmathresult$pi$


begindocument


begintikzpicture[>=latex]
datavisualization [
 school book axes, %scientific axes=clean,
 all axes=,
 x axis=
 label=$omega t$,
 ticks=
 step=(pi/2),
 tick typesetter/.code=mytypesetter##1,
 ,
 y axis=
 label=$v$, 
 ticks=none,
 ,
 style sheet=strong colors,
 style sheet=vary dashing,
 visualize as smooth line/.list=gerilim,
 gerilim=label in legend=text=$v$,
]
data [set=gerilim, format=function] 
 var x : interval [0:2*pi] samples 100;
 func y = 2*sin(value x r);
;
endtikzpicture 
enddocument

But that I want

.

How do I get this graph from my source code without using beginaxis[... endaxis?

tikz-pgf graphics tikz-shape tikz-decorations

share|improve this question

asked 2 hours ago

ÖzgürÖzgür

1,4421020

add a comment | 

MWE;

documentclass[tikz,border=10pt]standalone
usepackagetikz
usetikzlibrarydatavisualization
usetikzlibraryarrows,calc
usetikzlibraryshapes,positioning
usetikzlibrarydecorations.markings
usetikzlibrarydatavisualization.formats.functions
defmytypesetter#1
pgfmathparse#1/pi
pgfkeys/pgf/number format/precision=2
pgfmathroundtozerofillpgfmathresult
pgfmathifisintpgfmathresult
pgfmathprintnumberpgfmathresult$pi$

pgfmathprintnumber[/pgf/number format/frac, frac denom=2, frac whole=false]pgfmathresult$pi$


begindocument


begintikzpicture[>=latex]
datavisualization [
 school book axes, %scientific axes=clean,
 all axes=,
 x axis=
 label=$omega t$,
 ticks=
 step=(pi/2),
 tick typesetter/.code=mytypesetter##1,
 ,
 y axis=
 label=$v$, 
 ticks=none,
 ,
 style sheet=strong colors,
 style sheet=vary dashing,
 visualize as smooth line/.list=gerilim,
 gerilim=label in legend=text=$v$,
]
data [set=gerilim, format=function] 
 var x : interval [0:2*pi] samples 100;
 func y = 2*sin(value x r);
;
endtikzpicture 
enddocument

But that I want

.

How do I get this graph from my source code without using beginaxis[... endaxis?

tikz-pgf graphics tikz-shape tikz-decorations

share|improve this question

asked 2 hours ago

ÖzgürÖzgür

1,4421020

documentclass[tikz,border=10pt]standalone
usepackagetikz
usetikzlibrarydatavisualization
usetikzlibraryarrows,calc
usetikzlibraryshapes,positioning
usetikzlibrarydecorations.markings
usetikzlibrarydatavisualization.formats.functions
defmytypesetter#1
pgfmathparse#1/pi
pgfkeys/pgf/number format/precision=2
pgfmathroundtozerofillpgfmathresult
pgfmathifisintpgfmathresult
pgfmathprintnumberpgfmathresult$pi$

pgfmathprintnumber[/pgf/number format/frac, frac denom=2, frac whole=false]pgfmathresult$pi$


begindocument


begintikzpicture[>=latex]
datavisualization [
 school book axes, %scientific axes=clean,
 all axes=,
 x axis=
 label=$omega t$,
 ticks=
 step=(pi/2),
 tick typesetter/.code=mytypesetter##1,
 ,
 y axis=
 label=$v$, 
 ticks=none,
 ,
 style sheet=strong colors,
 style sheet=vary dashing,
 visualize as smooth line/.list=gerilim,
 gerilim=label in legend=text=$v$,
]
data [set=gerilim, format=function] 
 var x : interval [0:2*pi] samples 100;
 func y = 2*sin(value x r);
;
endtikzpicture 
enddocument

share|improve this question

asked 2 hours ago

ÖzgürÖzgür

1,4421020

share|improve this question

asked 2 hours ago

ÖzgürÖzgür

1,4421020

asked 2 hours ago

ÖzgürÖzgür

1,4421020

asked 2 hours ago

ÖzgürÖzgür

1,4421020

1 Answer
1

active

oldest

votes

3

A pure TikZ solution for fun, which is much shorter. I have no idea why you have to use datavisualization for this.

documentclass[tikz]standalone
usetikzlibrarypatterns
begindocument
begintikzpicture[>=latex,y=2cm]
draw[smooth,fill=red] plot[samples=100,domain=0:pi] (x,sin(deg(x)));
draw[smooth,pattern=horizontal lines,pattern color=red] plot[samples=100,domain=pi:2*pi] (x,sin(deg(x)));
draw[->] (0,-1.1)--(0,1.1) node[above] $v$;
draw[->] (-.2,0)--(2*pi+0.5,0) node[right] $omega t$;
draw (pi/2,-.05) node[below] $frac12pi$--(pi/2,.05);
draw (pi,-.05) node[below] $1pi$--(pi,.05);
draw (3*pi/2,-.05) node[below] $frac32pi$--(3*pi/2,.05);
draw (2*pi,-.05) node[below] $2pi$--(2*pi,.05);
draw (8.5,0) node tikzdraw[x=1pt,y=1pt] (0,0) to[out=30,in=-150] (20,0); $v$;
endtikzpicture
enddocument

share|improve this answer

answered 1 hour ago

JouleVJouleV

7,36721952

add a comment | 

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3

A pure TikZ solution for fun, which is much shorter. I have no idea why you have to use datavisualization for this.

documentclass[tikz]standalone
usetikzlibrarypatterns
begindocument
begintikzpicture[>=latex,y=2cm]
draw[smooth,fill=red] plot[samples=100,domain=0:pi] (x,sin(deg(x)));
draw[smooth,pattern=horizontal lines,pattern color=red] plot[samples=100,domain=pi:2*pi] (x,sin(deg(x)));
draw[->] (0,-1.1)--(0,1.1) node[above] $v$;
draw[->] (-.2,0)--(2*pi+0.5,0) node[right] $omega t$;
draw (pi/2,-.05) node[below] $frac12pi$--(pi/2,.05);
draw (pi,-.05) node[below] $1pi$--(pi,.05);
draw (3*pi/2,-.05) node[below] $frac32pi$--(3*pi/2,.05);
draw (2*pi,-.05) node[below] $2pi$--(2*pi,.05);
draw (8.5,0) node tikzdraw[x=1pt,y=1pt] (0,0) to[out=30,in=-150] (20,0); $v$;
endtikzpicture
enddocument

share|improve this answer

answered 1 hour ago

JouleVJouleV

7,36721952

add a comment | 

3

A pure TikZ solution for fun, which is much shorter. I have no idea why you have to use datavisualization for this.

documentclass[tikz]standalone
usetikzlibrarypatterns
begindocument
begintikzpicture[>=latex,y=2cm]
draw[smooth,fill=red] plot[samples=100,domain=0:pi] (x,sin(deg(x)));
draw[smooth,pattern=horizontal lines,pattern color=red] plot[samples=100,domain=pi:2*pi] (x,sin(deg(x)));
draw[->] (0,-1.1)--(0,1.1) node[above] $v$;
draw[->] (-.2,0)--(2*pi+0.5,0) node[right] $omega t$;
draw (pi/2,-.05) node[below] $frac12pi$--(pi/2,.05);
draw (pi,-.05) node[below] $1pi$--(pi,.05);
draw (3*pi/2,-.05) node[below] $frac32pi$--(3*pi/2,.05);
draw (2*pi,-.05) node[below] $2pi$--(2*pi,.05);
draw (8.5,0) node tikzdraw[x=1pt,y=1pt] (0,0) to[out=30,in=-150] (20,0); $v$;
endtikzpicture
enddocument

share|improve this answer

answered 1 hour ago

JouleVJouleV

7,36721952

add a comment | 

A pure TikZ solution for fun, which is much shorter. I have no idea why you have to use datavisualization for this.

documentclass[tikz]standalone
usetikzlibrarypatterns
begindocument
begintikzpicture[>=latex,y=2cm]
draw[smooth,fill=red] plot[samples=100,domain=0:pi] (x,sin(deg(x)));
draw[smooth,pattern=horizontal lines,pattern color=red] plot[samples=100,domain=pi:2*pi] (x,sin(deg(x)));
draw[->] (0,-1.1)--(0,1.1) node[above] $v$;
draw[->] (-.2,0)--(2*pi+0.5,0) node[right] $omega t$;
draw (pi/2,-.05) node[below] $frac12pi$--(pi/2,.05);
draw (pi,-.05) node[below] $1pi$--(pi,.05);
draw (3*pi/2,-.05) node[below] $frac32pi$--(3*pi/2,.05);
draw (2*pi,-.05) node[below] $2pi$--(2*pi,.05);
draw (8.5,0) node tikzdraw[x=1pt,y=1pt] (0,0) to[out=30,in=-150] (20,0); $v$;
endtikzpicture
enddocument

share|improve this answer

answered 1 hour ago

JouleVJouleV

7,36721952

documentclass[tikz]standalone
usetikzlibrarypatterns
begindocument
begintikzpicture[>=latex,y=2cm]
draw[smooth,fill=red] plot[samples=100,domain=0:pi] (x,sin(deg(x)));
draw[smooth,pattern=horizontal lines,pattern color=red] plot[samples=100,domain=pi:2*pi] (x,sin(deg(x)));
draw[->] (0,-1.1)--(0,1.1) node[above] $v$;
draw[->] (-.2,0)--(2*pi+0.5,0) node[right] $omega t$;
draw (pi/2,-.05) node[below] $frac12pi$--(pi/2,.05);
draw (pi,-.05) node[below] $1pi$--(pi,.05);
draw (3*pi/2,-.05) node[below] $frac32pi$--(3*pi/2,.05);
draw (2*pi,-.05) node[below] $2pi$--(2*pi,.05);
draw (8.5,0) node tikzdraw[x=1pt,y=1pt] (0,0) to[out=30,in=-150] (20,0); $v$;
endtikzpicture
enddocument

share|improve this answer

answered 1 hour ago

JouleVJouleV

7,36721952

answered 1 hour ago

JouleVJouleV

7,36721952

answered 1 hour ago

JouleVJouleV

7,36721952