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What is the accessibility of a package's `Private` context variables?



The 2019 Stack Overflow Developer Survey Results Are InHow symbol lookup actually worksWhat are recommended guidelines for developing packages?How to properly handle mutual imports of multiple packages?How can Private functions be made completely opaque?Does one need to be careful about loading multiple (many) contexts or packages in the same session?WebServices context problemHow to pass rules to packagesA question regarding shadowed symbolsIs there any harm or benefit to Removing unneeded private symbols in packages?Information (??) of function defined in Package return the function with long name of variablesHow to resolve a context shadow problem (revised)










4












$begingroup$


I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.



What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.



For example,



BeginPackage["CustomPackage`"]

MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."

Begin["`Private`"]

abc=5;
MyFunction[arg1_] := arg1 + abc;

End[]
EndPackage[]


When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`



So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath










share|improve this question











$endgroup$
















    4












    $begingroup$


    I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.



    What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.



    For example,



    BeginPackage["CustomPackage`"]

    MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."

    Begin["`Private`"]

    abc=5;
    MyFunction[arg1_] := arg1 + abc;

    End[]
    EndPackage[]


    When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`



    So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath










    share|improve this question











    $endgroup$














      4












      4








      4





      $begingroup$


      I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.



      What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.



      For example,



      BeginPackage["CustomPackage`"]

      MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."

      Begin["`Private`"]

      abc=5;
      MyFunction[arg1_] := arg1 + abc;

      End[]
      EndPackage[]


      When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`



      So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath










      share|improve this question











      $endgroup$




      I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.



      What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.



      For example,



      BeginPackage["CustomPackage`"]

      MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."

      Begin["`Private`"]

      abc=5;
      MyFunction[arg1_] := arg1 + abc;

      End[]
      EndPackage[]


      When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`



      So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath







      packages core-language scoping contexts






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 37 mins ago









      m_goldberg

      88.5k873200




      88.5k873200










      asked 3 hours ago









      w1resw1res

      1984




      1984




















          3 Answers
          3






          active

          oldest

          votes


















          5












          $begingroup$


          So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath




          There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.



          $Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.



          Load the package and try this:



          Block[$ContextPath,
          Print@Definition[MyFunction]
          ]


          You'll see the following printed:



          CustomPackage`MyFunction[CustomPackage`Private`arg1_] := 
          CustomPackage`Private`arg1+CustomPackage`Private`abc


          As you can see, a context is always associated with every symbol.






          share|improve this answer











          $endgroup$




















            4












            $begingroup$

            All symbols are created at load time, so when you do:



            BeginPackage["X`"];

            x::usage="Declaring x as an exported symbol in the X` context";

            Begin["`SomePrivateContext`"];

            x[a_]:=b

            End[];

            EndPackage[];


            x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.






            share|improve this answer









            $endgroup$




















              4












              $begingroup$

              Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:



              • The symbol abc will be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along $ContextPath.


              • If no matching symbol is found this way, a new symbol abc is created, namely in the current $Context which is "CustomPackage`Private`". So the full symbol name is "CustomPackage`Private`abc".


              For example, running your code in a fresh kernel and executing



              ??MyFunction


              reveals that the full definition of MyFunction is




              MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc




              Moreover, with



               ?*`abc


              you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.






              share|improve this answer











              $endgroup$













                Your Answer





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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                5












                $begingroup$


                So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath




                There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.



                $Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.



                Load the package and try this:



                Block[$ContextPath,
                Print@Definition[MyFunction]
                ]


                You'll see the following printed:



                CustomPackage`MyFunction[CustomPackage`Private`arg1_] := 
                CustomPackage`Private`arg1+CustomPackage`Private`abc


                As you can see, a context is always associated with every symbol.






                share|improve this answer











                $endgroup$

















                  5












                  $begingroup$


                  So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath




                  There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.



                  $Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.



                  Load the package and try this:



                  Block[$ContextPath,
                  Print@Definition[MyFunction]
                  ]


                  You'll see the following printed:



                  CustomPackage`MyFunction[CustomPackage`Private`arg1_] := 
                  CustomPackage`Private`arg1+CustomPackage`Private`abc


                  As you can see, a context is always associated with every symbol.






                  share|improve this answer











                  $endgroup$















                    5












                    5








                    5





                    $begingroup$


                    So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath




                    There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.



                    $Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.



                    Load the package and try this:



                    Block[$ContextPath,
                    Print@Definition[MyFunction]
                    ]


                    You'll see the following printed:



                    CustomPackage`MyFunction[CustomPackage`Private`arg1_] := 
                    CustomPackage`Private`arg1+CustomPackage`Private`abc


                    As you can see, a context is always associated with every symbol.






                    share|improve this answer











                    $endgroup$




                    So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath




                    There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.



                    $Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.



                    Load the package and try this:



                    Block[$ContextPath,
                    Print@Definition[MyFunction]
                    ]


                    You'll see the following printed:



                    CustomPackage`MyFunction[CustomPackage`Private`arg1_] := 
                    CustomPackage`Private`arg1+CustomPackage`Private`abc


                    As you can see, a context is always associated with every symbol.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 2 hours ago

























                    answered 2 hours ago









                    SzabolcsSzabolcs

                    164k14448946




                    164k14448946





















                        4












                        $begingroup$

                        All symbols are created at load time, so when you do:



                        BeginPackage["X`"];

                        x::usage="Declaring x as an exported symbol in the X` context";

                        Begin["`SomePrivateContext`"];

                        x[a_]:=b

                        End[];

                        EndPackage[];


                        x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.






                        share|improve this answer









                        $endgroup$

















                          4












                          $begingroup$

                          All symbols are created at load time, so when you do:



                          BeginPackage["X`"];

                          x::usage="Declaring x as an exported symbol in the X` context";

                          Begin["`SomePrivateContext`"];

                          x[a_]:=b

                          End[];

                          EndPackage[];


                          x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.






                          share|improve this answer









                          $endgroup$















                            4












                            4








                            4





                            $begingroup$

                            All symbols are created at load time, so when you do:



                            BeginPackage["X`"];

                            x::usage="Declaring x as an exported symbol in the X` context";

                            Begin["`SomePrivateContext`"];

                            x[a_]:=b

                            End[];

                            EndPackage[];


                            x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.






                            share|improve this answer









                            $endgroup$



                            All symbols are created at load time, so when you do:



                            BeginPackage["X`"];

                            x::usage="Declaring x as an exported symbol in the X` context";

                            Begin["`SomePrivateContext`"];

                            x[a_]:=b

                            End[];

                            EndPackage[];


                            x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 3 hours ago









                            b3m2a1b3m2a1

                            28.6k359165




                            28.6k359165





















                                4












                                $begingroup$

                                Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:



                                • The symbol abc will be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along $ContextPath.


                                • If no matching symbol is found this way, a new symbol abc is created, namely in the current $Context which is "CustomPackage`Private`". So the full symbol name is "CustomPackage`Private`abc".


                                For example, running your code in a fresh kernel and executing



                                ??MyFunction


                                reveals that the full definition of MyFunction is




                                MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc




                                Moreover, with



                                 ?*`abc


                                you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.






                                share|improve this answer











                                $endgroup$

















                                  4












                                  $begingroup$

                                  Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:



                                  • The symbol abc will be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along $ContextPath.


                                  • If no matching symbol is found this way, a new symbol abc is created, namely in the current $Context which is "CustomPackage`Private`". So the full symbol name is "CustomPackage`Private`abc".


                                  For example, running your code in a fresh kernel and executing



                                  ??MyFunction


                                  reveals that the full definition of MyFunction is




                                  MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc




                                  Moreover, with



                                   ?*`abc


                                  you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.






                                  share|improve this answer











                                  $endgroup$















                                    4












                                    4








                                    4





                                    $begingroup$

                                    Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:



                                    • The symbol abc will be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along $ContextPath.


                                    • If no matching symbol is found this way, a new symbol abc is created, namely in the current $Context which is "CustomPackage`Private`". So the full symbol name is "CustomPackage`Private`abc".


                                    For example, running your code in a fresh kernel and executing



                                    ??MyFunction


                                    reveals that the full definition of MyFunction is




                                    MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc




                                    Moreover, with



                                     ?*`abc


                                    you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.






                                    share|improve this answer











                                    $endgroup$



                                    Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:



                                    • The symbol abc will be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along $ContextPath.


                                    • If no matching symbol is found this way, a new symbol abc is created, namely in the current $Context which is "CustomPackage`Private`". So the full symbol name is "CustomPackage`Private`abc".


                                    For example, running your code in a fresh kernel and executing



                                    ??MyFunction


                                    reveals that the full definition of MyFunction is




                                    MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc




                                    Moreover, with



                                     ?*`abc


                                    you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.







                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited 3 hours ago

























                                    answered 3 hours ago









                                    Henrik SchumacherHenrik Schumacher

                                    59.7k582166




                                    59.7k582166



























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